Question
Asked Oct 25, 2019

A 2.0 kg rock is pressed up a distance ∆x = 20 cm against a spring with spring constant 400 N/m and then released, causing it to slide across a frictionless horizontal surface and then to slide down a frictonless incline. At the bottom of the incline is a horizontal surface that has a coe cent of kinetic friction μk = 0.80 with the rock, which causes the rock to come to rest in L = 1.5 m. (a) Fill out the Energy Chart below to calculate the Potential and Kinetic Energy at each time point. Use g = 10 m/s2 for easier calcuations. Assume Energy is Conserved UNTIL the rock reaches the rough surface.

Scene A
Ax
Scene C
h =?
Scene B
h 0 cm
(b) What is the initial height, h?
Scene B
Scene A
Scene C
PEgravity
mgh
KE
= }mu2
PEspring
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Scene A Ax Scene C h =? Scene B h 0 cm (b) What is the initial height, h? Scene B Scene A Scene C PEgravity mgh KE = }mu2 PEspring

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Expert Answer

Step 1

(a)

Scene A

The potential energy due to gravity is,

Substitute the values,

PE
ity
mgAr
'0.0lm
-(2.0kg)(10m/s')(20Cm)
PE
lan
-4.0J
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PE ity mgAr '0.0lm -(2.0kg)(10m/s')(20Cm) PE lan -4.0J

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Step 2

Scene B

The potential energy due to gravity is,

Substitute the values,

Scene C

The potential energy due to gravity is,

PE mgh
-(2.0kg)(10m/s'0cm)
PE
=0J
PE 0J
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PE mgh -(2.0kg)(10m/s'0cm) PE =0J PE 0J

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Step 3

From the conservation of energy

S...

1
2
-2gh
v=2gh
210m/*X0.2m)
2.0m/s
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1 2 -2gh v=2gh 210m/*X0.2m) 2.0m/s

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