Life time of a TCP segment is defined as thetime for which a TCP segment is permittedto stay in a network. Consider a TCPconnection has Bandwidth of 8 GBPS andlifetime of a TCP segment is 4 seconds.The number of extra bits required fromoptions field if the user doesn't want todecrease the Bandwidth?

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Answered: segment is defir P segment is p E.…

Engineering

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segment is defir P segment is p E. Consider a TC

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Life time of a TCP segment is defined as the
time for which a TCP segment is permitted
to stay in a network. Consider a TCP
connection has Bandwidth of 8 GBPS and
lifetime of a TCP segment is 4 seconds.
The number of extra bits required from
options field if the user doesn't want to
decrease the Bandwidth?

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. If size of a TCP segment is 1KB and header length value is 6, the sequence number = 3500. Given that URG flag = 1 and URG pointer = 45. Then what is the total size of data. How many of them are urgent, Give the sequence numbers of urgent data.
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In TCP Fast Retransmit, if we receive three duplicate ACKS after sending out a packet that is not incrementally ACK-ed but before the time-out associated with that packet, we immediately retransmit the packet without waiting for the timeout to occur. Why do we wait for three duplicates instead of just one?
Suppose Host A sends two consecutive TCP segments to Host B over a TCP connection. The sequence number of the first segment is 748, and the sequence number of the second one is 995. Determine the size of the payload carried by the first segment. Suppose that the first segment is lost but the second segment arrives at host B. What will be the acknowledgment number of the acknowledgment segment that Host B sends to Host A?
Is it right or wrong? Let's pretend the most recent SampleRTT on your TCP connection was 1 second. The connection's current TimeoutInterval value must be greater than one second.
Consider the figure below in which a TCP sender and receiver communicate over a connection in which the sender->receiver segments may be lost. The TCP sender sends an initial window of 5 segments. Suppose the initial value of the sender->receiver sequence number is 362 and the first 5 segments each contain 638 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t=8. As shown in the figure below, 3 of the 5 segment(s) are lost between the segment and receiver.
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The QUIC protocol must perform dependability and other TCP features on UDP in order to give HTTP True False 00.
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The filed “window size” in TCP header is in length of 16 bit. It allows 64KB as the maximal size for a TCP segment by default. Under some circumstances, the sending rate is pretty high and it results in a very short sending time (<2ms). But the end to end transmission delay is 50ms. Therefore the idle rate of a channel will be more than 2/3 . How does TCP solve this problem?
UDP implementation of dependability and other TCP features is required in order for the QUIC protocol to provide HTTP True False 00.
Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. The TCP sender wants to send a total of 10 segments to the receiver and sends an initial window of 5 segments at t = 1, 2, 3, 4, and 5, respectively. Suppose the initial value of the sequence number is 151 and every segment sent to the receiver each contains 612 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. As shown in the figure, 1 of the 5 segments is lost between the sender and the receiver, but none of the ACKs are lost. Assume there are no timeouts and any out of order segments received are thrown out.