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Select the pair of products formed in the electrolysis of a solution of ZrCl4(aq) using inert electrodes. Assume that there are no overpotentials involved in any reactions. Standard reduction potentials are hs Cl₂(g) +2 e 2 Cl¯(aq) E° = +1.36 V O2(g) + 4 H*(aq) + 4 e → 2 H2O(I) 2 H2O(I) + 2 e → H2(g) + 2 OH (aq) E° = -0.83 V Zr4+ (aq) + 4 e H₂ and Cl₂ H₂ and O2 Zr and H₂ Zr and Cl₂ Zr and O₂ M Zr(s) E° = +1.23 V E° = -1.53 V

Select the pair of products formed in the electrolysis of a solution of ZrCl4(aq) using inert electrodes. Assume that there are no overpotentials involved in any reactions. Standard reduction potentials are hs Cl₂(g) +2 e 2 Cl¯(aq) E° = +1.36 V O2(g) + 4 H*(aq) + 4 e → 2 H2O(I) 2 H2O(I) + 2 e → H2(g) + 2 OH (aq) E° = -0.83 V Zr4+ (aq) + 4 e H₂ and Cl₂ H₂ and O2 Zr and H₂ Zr and Cl₂ Zr and O₂ M Zr(s) E° = +1.23 V E° = -1.53 V

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Faraday Constant: F = 96,485.3 C/mol Gas Constant: R = 8.3145 J K-1 mol-1 = 0.082057 L atm K-1 mol-1 Pressure: 1 atm = 1.01325 bar = 760 Torr Temperature: 273.15 K = 0 °C = RT/F = 0.025693 V at T = 298.15 K 101325 Pa
Transcribed Image Text:Faraday Constant: F = 96,485.3 C/mol Gas Constant: R = 8.3145 J K-1 mol-1 = 0.082057 L atm K-1 mol-1 Pressure: 1 atm = 1.01325 bar = 760 Torr Temperature: 273.15 K = 0 °C = RT/F = 0.025693 V at T = 298.15 K 101325 Pa
Select the pair of products formed in the electrolysis of a solution of ZrCl4(aq) using inert electrodes. Assume that there are no overpotentials involved in any reactions. Standard reduction potentials are Cl₂(g) + 2 e 2 Cl¯(aq) E° = +1.36 V O2(g) + 4 H*(aq) + 4 e − 2 H2O(I) 2 H2O(l) + 2 e → H2(g) + 2 OH (aq) E° = -0.83 V Zr4+ (aq) + 4e¯ → Zr(s) H₂ and Cl₂ H₂ and O2 Zr and H₂ Zr and Cl₂ Zr and O2 E° = +1.23 V E° = -1.53 V
Transcribed Image Text:Select the pair of products formed in the electrolysis of a solution of ZrCl4(aq) using inert electrodes. Assume that there are no overpotentials involved in any reactions. Standard reduction potentials are Cl₂(g) + 2 e 2 Cl¯(aq) E° = +1.36 V O2(g) + 4 H*(aq) + 4 e − 2 H2O(I) 2 H2O(l) + 2 e → H2(g) + 2 OH (aq) E° = -0.83 V Zr4+ (aq) + 4e¯ → Zr(s) H₂ and Cl₂ H₂ and O2 Zr and H₂ Zr and Cl₂ Zr and O2 E° = +1.23 V E° = -1.53 V
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