Set the value of the variable a to be 191 Set the value of the variable b to be 3 If a is divisible by 3, then do the following: | replace the value of b by 2•b othervise, if a is divisible by 2, do the following: replace the value of b by 3+b othervise, replace the value of b by 5 b replace the value of a vith a + b

Set the value of the variable a to be 191 Set the value of the variable b to be 3 If a is divisible by 3, then do the following: | replace the value of b by 2•b othervise, if a is divisible by 2, do the following: replace the value of b by 3+b othervise, replace the value of b by 5 b replace the value of a vith a + b

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter8: Arrays And Strings

Section: Chapter Questions

Problem 21PE

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When you borrow money to buy a house, a car, or for some other purposes, then you typically repay it by making periodic payments. Suppose that the loan amount is L, r is the interest rate per year, m is the number of payments in a year, and the loan is for t years. Suppose that i = (r / m) and r is in decimal. Then the periodic payment is: You can also calculate the unpaid loan balance after making certain payments. For example, the unpaid balance after making k payments is: where R is the periodic payment. (Note that if the payments are monthly, then m = 12.) Instructions Write a program that prompts the user to input the values of L, r, m, t, and k. The program then outputs the appropriate values. Your program must contain at least two functions, with appropriate parameters, to calculate the periodic payments and the unpaid balance after certain payments. Make the program menu driven and use a loop so that the user can repeat the program for different values. Example of…
HALP m + n = 2k + 2k = 4k therefore adding even numbers always gives an even number. The above is wrong because.... it doesn't consider the case when adding to odd numbers m and n are different so you cannot use 2k for both it doesn't consider what m and n are for particular values in the integers it doesn't consider the case when m is even and n is odd
Rahul is a maths genius so he came up with a game and as raj is Rahul's best friend so Rahul decided to play the game with raj. Rahul gives raj two numbers LL and RR and asks raj to find the count of numbers in the range from LL to RR (LL and RR inclusive) which are a digit palindromic. A number is a digit palindromic if its first digit is the same as its last digit. As raj is not very good at maths so your task is to help Raj find out how many numbers are a digit palindromic in the range LL to RR. For example if LL = 88 and RR = 2525 .The following numbers are a digit palindromic in the range of LL to RR: 8, 9, 11, and 22. If LL = 12511251 and RR = 12661266. The digit palindromic numbers are 1251 and 1261. Input format The first line contains an integer denoting the number of test cases. Each test case is described by a single line that contains two integers LL and RR. Output format For each test case output, an integer denoting how many a digit palindromic numbers are there in the…
Blackout Math is a math puzzle in which you are given an incorrect arithmetic equation. The goal of the puzzle is to remove two of the digits and/or operators in the equation so that the resulting equation is correct. For example, given the equation 6 - 5 = 15 ^ 4/2 we can remove the digit 5 and the / operator from the right-hand side in order to obtain the correct equality 6 - 5 = 1 ^ 42. Both sides of the equation now equal to 1. Observe how removing an operator between two numbers (4 and 2) causes the digits of the numbers to be concatenated (42). Here is a more complicated example: 288 / 24 x 6 = 18 x 13 x 8 We can remove digits and operators from either side of the equals sign (either both from one side, or one on each side). In this case, we can remove the 2 from the number 24 on the left-hand side and the 1 from the number 13 on the right-hand side to obtain the correct equality 288 / 4 x 6 = 18 x 3 x 8 Both sides of the equation now equal to 432. Here is another puzzle for you…
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Not pseudocode Suppose the economies of the world use a set of currencies C1, . . . , Cn; think of these as dollars, pounds, Bitcoin, etc. Your bank allows you to trade each currency Ci for any other currency Cj, and finds some way to charge you for this service. Suppose that for each ordered pair of currencies (Ci, Cj ), the bank charges a flat fee of fij > 0 dollars to exchange Ci for Cj (regardless of the quantity of currency being exchanged). Describe an algorithm which, given a starting currency Cs, a target currency Ct, and a list of fees fij for all i, j ∈ {1, . . . , n}, computes the cheapest way (that is, incurring the least in fees) to exchange all of our currency in Cs into currency Ct. Also, justify the its runtime. [We are expecting a description of the algorithm, as well as a brief justification of its runtime.]
The interest paid on a savings account is compounded daily. This means that if you start with startbal dollars in the bank, at the end of the first day you’ll have a balance ofstartbal * (1 + rate/365)dollars, where rate is the annual interest rate (0.10 if the annual rate is 10 percent). At the end of the second day, you’ll havestartbal * (1 + rate/365) * (1 + rate/365)dollars, and at the end of n days you’ll havestartbal * (1 + rate/365)ndollars. Write a program that processes a set of data records, each of which contains values for rate, startbal, and n and computes the final account balance.
Blackout Math is a math puzzle in which you are given an incorrect arithmetic equation. The goal of the puzzle is to remove two of the digits and/or operators in the equation so that the resulting equation is correct. For example, given the equation 6 - 5 = 15 ^ 4/2we can remove the digit 5 and the / operator from the right-hand side in order to obtain the correct equality 6 - 5 = 1 ^ 42. Both sides of the equation now equal to 1. Observe how removing an operator between two numbers (4 and 2) causes the digits of the numbers to be concatenated (42). Here is a more complicated example: 288 / 24 x 6 = 18 x 13 x 8 We can remove digits and operators from either side of the equals sign (either both from one side, or one on each side). In this case, we can remove the 2 from the number 24 on the left-hand side and the 1 from the number 13 on the right-hand side to obtain the correct equality 288 / 4 x 6 = 18 x 3 x 8 Both sides of the equation now equal to 432. Here is another puzzle for you…
Write this uing java Write a complete version of the Bresenham Midpoint algorithm to handle ALL slope values. slope = 0 slope > 0 slope < 0 slope = 1 slope > 1 swap the rolls of x and y slope < 1 slope = infinity ( needs special test case) Include appropriate tests for ‘special case’ conditions. Insteadof “WritePixel” write to the screen the coordinates of the pixel that would be drawn.
JAVA CODE PLS Rectangle by CodeChum Admin A rectangle can be formed given two points, the top left point and the bottom right point. Assuming that the top left corner of the console is point (0,0), the bottom right corner of the console is point (MAX, MAX) and given two points (all "x" and "y" coordinates are positive), you should be able to draw the rectangle in the correct location, determine if it is a square or a rectangle, and compute for its area, perimeter and center point. To be able to do this, you should create a class for a point (that has an x-coordinate and a y-coordinate). Also, create another class called Rectangle. The Rectangle should have 2 points, the top left and the bottom right. You should also implement the following methods for the Rectangle: display() - draws the rectangle on the console based on the sample area() - computes and returns the area of a given rectangle perimeter() - computes and returns the perimeter of a given rectangle centerPoint() -…