Short answer: 1. Sodium reacts with water to produce hydrogen gas and sodium hydroxide. If 15 g of sodium are added to 75 grams of water, calculate the mass of hydrogen gas that is produced. 2. Calculate the mass (in grams) of sodium sulfide that is needed to make 350 mL of a 0.50 mol/L solution. 3.In a lab 42.6 mL. of sulfuric acid precipitates exactly 3.260 g of barium sulfate from a solution of barium hydroxide. What is the molar concentration of the sulfuric acid?
Short answer: 1. Sodium reacts with water to produce hydrogen gas and sodium hydroxide. If 15 g of sodium are added to 75 grams of water, calculate the mass of hydrogen gas that is produced. 2. Calculate the mass (in grams) of sodium sulfide that is needed to make 350 mL of a 0.50 mol/L solution. 3.In a lab 42.6 mL. of sulfuric acid precipitates exactly 3.260 g of barium sulfate from a solution of barium hydroxide. What is the molar concentration of the sulfuric acid?
Introductory Chemistry: A Foundation
8th Edition
ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter15: Solutions
Section: Chapter Questions
Problem 116AP: A large beaker contains 1.50 L of a 2.00 M iron(III) chloride solution. How many moles of iron ions...
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Short answer:
1. Sodium reacts with water to produce hydrogen gas and sodium hydroxide.
If 15 g of sodium are added to 75 grams of water, calculate the mass of hydrogen gas that is produced.
2. Calculate the mass (in grams) of sodium sulfide that is needed to make 350 mL of a 0.50 mol/L solution.
3.In a lab 42.6 mL. of sulfuric acid precipitates exactly 3.260 g of barium sulfate from a solution of barium hydroxide. What is the molar concentration of the sulfuric acid?
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