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Show that, given a 7-digit number, where all digits except perhaps the last is non-zero, you can cross out some digits at the beginning and at the end such that the remaining number consists of at least one digit and is divisible by 7. For example, if we take the number 1234589, then we can cross out 1 at the beginning and 89 at the end to get the number 2345 = 7 x 335.

Show that, given a 7-digit number, where all digits except perhaps the last is non-zero, you can cross out some digits at the beginning and at the end such that the remaining number consists of at least one digit and is divisible by 7. For example, if we take the number 1234589, then we can cross out 1 at the beginning and 89 at the end to get the number 2345 = 7 x 335.

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter11: Rational And Irrational Numbers
Section11.8: Adding And Subtracting Radicals
Problem 5E
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Show that, given a 7-digit number, where all digits except perhaps the last is non-zero, you can cross out some digits at the beginning and at the end such that the remaining number consists of at least one digit and is divisible by 7. For example, if we take the number 1234589, then we can cross out 1 at the beginning and 89 at the end to get the number 2345 = 7 x 335.
Transcribed Image Text:Show that, given a 7-digit number, where all digits except perhaps the last is non-zero, you can cross out some digits at the beginning and at the end such that the remaining number consists of at least one digit and is divisible by 7. For example, if we take the number 1234589, then we can cross out 1 at the beginning and 89 at the end to get the number 2345 = 7 x 335.
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