sin x x0 sin Vx sin (x2 + x) 26. lim 28. lim sin (Vx-3) 30. lim x - 9

Q: lim x→0  2 ln x.

A:

Q: lim x approaches 0 ................ (1 + x + sin x) / (3 cos x)

A:

Q: lim cos x→0+

A: Given lim×-0 cos (1/x) For the above limit we have to solve it first

Q: lim sin x x aproches infinity

A: We need to determine the value of the following limit

Q: lim X-3 Sinx X-0

A: Limit of a function

Q: (+) C lim x sin sin(3x) lim- 0 sin(4x) sin (x-1) lim 1 1-x+x² -x'

A:

Q: L’Hôpital’s Rule is used incorrectly. Describe the error.

A:

Q: lim Sin (x-B) XB (x-B)

A:

Q: lim x→0 sinh x2 – x2 sinhx−x

A:

Q: im x→0 tan(2x)/x

A:

Q: Lim x-0 e³ +ex -x²-2 sin² x-x²

A:

Q: lim sin(x)dx (x² + e²)²

A:

Q: sin(3 – x) lim с2 — 5х + 6 x→2 x2 – 5x + 6

A:

Q: limx→0  xcos(x)-sin(x)/x^3

A: Given: The limit limx→0xcosx-sinxx3, To find: The value of the limit.

Q: lim (sec x)cot x X→; 2

A: We have to find out

Q: sinx lim X→0 5x a. 3(1– co x) lim b. (sinx) (1- cosx) lim С. x²

A:

Q: lim x-6 x-4 |7-x| lim x-7 7-x 10 sin x lim x-0 6x

A:

Q: lim sin (–3 x z) = z-3

A: To find- the limit.

Q: lim x→0 (sin 4x/ sin 6x)

A:

Q: limx>0 sin-1x/x

A: So, now we apply L' hospital rule to evaluate the given function. Because if we directly apply the…

Q: Lim 2-2 cosx - xIn (1+x). x sin'x

A: We apply L hospital rule to find the limt. See 2nd,3rd and 4th step.

Q: Find the limit

A: Recall:

Q: sin(3 – x) lim x→1 x2 – 5x + 6

A: Explained below

Q: lim 1-e*) X-0 x sin x

A:

Q: sin 14x lim x-0 sin 7x 3x (7x – 2) lim x+0 \7x + 3.

A: limx→0sin14xsin7xAs we know that if limx→a-f(x)=limx→a+f(x)=Llimx→0sin(14x)sin(7x)=00This is…

Q: sin x-coS X Determine el límite: lim 1-cotx

A: The given expression is limx→π4sinx-cosx1-cotx. Evaluate the limit as shown below.

Q: limx>0 (x-sin(x))/xsin(x)

A: Given,          limx→0x-sinxxsinx

Q: lim sin(5x) csc(3x) X-0

A: Formula: LimX→0[sin(ax)/x]=a

Q: lim *+ x cos x X0 sin x cos x

A: Given:       To determine: The value of the limit.

Q: Lim x tends to pi/4- (LHL) √(1-√sin2x)/(pi - 4x)

A:

Q: Find the limit

A:

Q: Evaluate the limit.

A: To evaluatelimx→0sin5xsin2xsin3xsin5x

Q: sin (x-1) lim x+1 x2+2x-3

A: To evaluate: limx→1 sin⁡(x−1)x2+2x−3 The given limit is of indeterminant form 0/0

Q: sin(4z) f(x) = 9x 0.4 0.35 0.3 0.25 0/5 -0.25 0.25 sin(4x) Evaluate lim 9x Enter at least 3 decimal…

A: Let's find.

Q: lim x → 0 sin^8 x / x

A:

Q: lim sin (2 – 2) cot² (x² – x – 2)

A: We have to find

Q: lim (sec³ x – tan n³ x)

A: We have to evaluate the given limit: limx→π2sec3 x-tan3 x We know the identities, sec x=1cos xtan…

Q: (sin(2x)+7x2-2х 3. lim x→0 х4+2х3+x2

A:

Q: lim x -> pi/4 sinx-cosx/1-tanx

A:

Q: sin 2x tan xsin 4x 2. Determine lim You may NOT use L'Hospital's x2 sin 3x rule.

A:

Q: 2 sin(x)-sin(2x) х-sin(x) lim X→0

A: Given,           limx→02sinx-sin2xx-sinx

Q: lim X-3 Sinx X->o

A:

Q: sin (1 cos x) sin x -0" sin Vx sin (x2 + x) 25. lim 26. lim sin (sin x) 27. lim 28. lim sin (x - 4)…

A:

Q: sin 7x 9. lim 9.h x→0 sin 3x

A: GIVEN limx→0sin7xsin 3x

Q: lim x->0  ((1-x^2)/(x^2))^(tanhx)    using l'hospitals

A: Use l'hopital rule

Q: lim cos(x) X- +x 3 TC 2.

A:

Q: evaluate the limit.

A: Given integral is When x=0 Therefore, by applying L'Hopitals' Rule, we have

Q: sin 5x 17) lim х-0 sin x

A:

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.