size n = 10 with μ' = (5 Let X ~N, (1, 2) −2 4) 6 5 -3 Σ = 5 7 0 -3 0 4 1. find the distribution of X, and (X₁, X₂) X₁ - X₂ 2. find the distribution X₁ + X₂ −X₂] 3. Are X-X, and X₁ + X, X, independent. - 3 4. find the distribution of Y. and NO
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- Let X = Red blood cell count in millions per cubic millimeter of whole blood for healthy females ex has been approximately normal distribution which means U = 5.1 and standard deviation O = 0.6 (a) Convert the x interval, 4.5 < x, to a z interval. (Round your answer to two decimal places.) (b) Convert the x interval, x < 4.2, to a z interval. (Round your answer to two decimal places.) (c) Convert the x interval, 4.0 < x < 5.5, to a z interval. (Round your answers to two decimal places.) (d) Convert the z interval, z < -1.44, to an x interval. (Round your answer to one decimal place.) (e) Convert the z interval, 1.28 < z, to an x interval. (Round your answer to one decimal place.) (f) Convert the z interval, -2.25 < z < -1.00, to an x interval. (Round your answers to one decimal place)4.4. An individual picked at random from a population has a propensity to have accidents that is modelled by a random variable Y having the gamma distribution with shape parameter α and rate parameter β. Given Y = y, the number of accidents that the individual suffers in years 1, 2, . . . , n are independent random variables X1, X2, . . . Xn each having the Poisson distribution with parameter y. (a) Write down a function f so that the joint distribution of Y, X1, . . . , Xn can be described via P(a ≤ Y ≤ b, X1 = k1, X2 = k2 . . . Xn = kn) = Z b a f(y, k1, k2, . . . kn)dy and derive from this expression that, for your choice of f, Y has the Gamma distribution, and that conditionally on Y = y, X1, X2, . . . Xn are independent, each having the Poisson distribution with parameter y. (b) Find the conditional distribution of Y given that X1 = k1, X2 = k2, . . . , kn. (c) An insurance company has observed the number of accidents that an individual has suffered on each of n years and wishes to…Find the area under the standard normal curve to the right of z = 2.04 z= 1.09 Genetics: Pea plants contain two genes for seed color, each of which may be Y (for yellow seeds) or G (for green seeds). Plants that contain one of each type of gene are called heterozygous. According to the Mendelian theory of genetics, if two heterozygous plants are crossed, each of their offspring will have probability 0.75 of having yellow seeds and probability 0.25 of having green seeds. One hundred such offspring are produced. Approximate the probability that more than 30 have green seeds.
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