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Sketch a standard normal curve and shade the area that lies to the left of a. 2.19, b. -1.63, c. 0, and d. -5. Then determine the area under the standard normal curve that lies in the area of interest for each part. Click here to view page 1 of the normal distribution table. Click here to view page 2 of the normal distribution table, The area to the left of 2.19 is 0.9857 (Round to four decimal places as needed.) b. Sketch a standard normal curve and shade the area under the curve that lies to the left of -1.63. torrec Choose the correct graph below. OD. OA OB. Q -1.63 -1.63 1.63 The area to the left of -1.63 is (Round to four decimal places as needed.) Q

Sketch a standard normal curve and shade the area that lies to the left of a. 2.19, b. -1.63, c. 0, and d. -5. Then determine the area under the standard normal curve that lies in the area of interest for each part. Click here to view page 1 of the normal distribution table. Click here to view page 2 of the normal distribution table, The area to the left of 2.19 is 0.9857 (Round to four decimal places as needed.) b. Sketch a standard normal curve and shade the area under the curve that lies to the left of -1.63. torrec Choose the correct graph below. OD. OA OB. Q -1.63 -1.63 1.63 The area to the left of -1.63 is (Round to four decimal places as needed.) Q

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section: Chapter Questions
Problem 22SGR
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Sketch a standard normal curve and shade the area that lies to the left of a. 2.19, b. -1.63, c. 0, and d. -5. Then determine the area under the standard normal curve that lies in the area of interest for each part. Click here to view page 1 of the normal distribution table. Click here to view page 2 of the normal distribution table. The area to the left of 2.19 is 0.9857. (Round to four decimal places as needed.) 3 b. Sketch a standard normal curve and shade the area under the curve that lies to the left of -1.63. correct: C Choose the correct graph below. OD. OB. OA Q Q -1.63 0 1.63 -1.63 The area to the left of -1.63 is. (Round to four decimal places as needed.) -1.63 6 4 R 5 6 Y & 7 8
Transcribed Image Text:Sketch a standard normal curve and shade the area that lies to the left of a. 2.19, b. -1.63, c. 0, and d. -5. Then determine the area under the standard normal curve that lies in the area of interest for each part. Click here to view page 1 of the normal distribution table. Click here to view page 2 of the normal distribution table. The area to the left of 2.19 is 0.9857. (Round to four decimal places as needed.) 3 b. Sketch a standard normal curve and shade the area under the curve that lies to the left of -1.63. correct: C Choose the correct graph below. OD. OB. OA Q Q -1.63 0 1.63 -1.63 The area to the left of -1.63 is. (Round to four decimal places as needed.) -1.63 6 4 R 5 6 Y & 7 8
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