Solid BaSO4 dissolves to give its constituent ions in aqueous solution: BaSO4(s) = Ba²*(aq) + SO4²(aq) 1.1x10-10 (at 298 K) Ksp = When some 0.010 M Ba(NO3)2 is added to the equilibrium, 2+ O The Ba is the common ion, and the solubility of BaSO4 decreases. O The NO3 is the common ion, and there will be an increase in the solubility of BaSO4. O The Ba2+ is the common ion, and the solubility of BaSO4 increases. O The NO3 is the common ion, and the solubility of BaSO4 decreases. II

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Chapter12: Chemical Equilibrium
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Solid BaSO4 dissolves to give its constituent ions in
aqueous solution:
BaSO4(s) = Ba2*(aq) + SO42(aq)
1.1x10-10 (at 298 K)
Ksp =
When some 0.010 M Ba(NO3)2 is added to the
equilibrium,
O The Ba2+ is the common ion, and the solubility of
BaSO4 decreases.
O The NO3 is the common ion, and there will be an
increase in the solubility of BaSO4.
O The Ba2+ is the common ion, and the solubility of
BaSO4 increases.
O The NO3 is the common ion, and the solubility of
BaSO4 decreases.
Transcribed Image Text:Solid BaSO4 dissolves to give its constituent ions in aqueous solution: BaSO4(s) = Ba2*(aq) + SO42(aq) 1.1x10-10 (at 298 K) Ksp = When some 0.010 M Ba(NO3)2 is added to the equilibrium, O The Ba2+ is the common ion, and the solubility of BaSO4 decreases. O The NO3 is the common ion, and there will be an increase in the solubility of BaSO4. O The Ba2+ is the common ion, and the solubility of BaSO4 increases. O The NO3 is the common ion, and the solubility of BaSO4 decreases.
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