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The slightly soluble salt fluorapatite, Cas(PO4)3F, has a Ksp = 1 x 1031. It dissociates in water according to the following equation: Cas(PO4)3F(s) 5Ca2+ +3 PO43- + F Write the Ksp equation for this process: Ksp = 1. 2. Calculate the equilibrium concentrations of Ca2+, PO43- , and F. a. [Ca2] = b. [PO43-]= c. [F] = How many grams of fluorapatite will dissolve in 1L of water? 3. 4. The solubility of the related salt hydroxyapatite, Cas(PO4)30H (Ksp 1 x 10-29), is affected by the pH of the water to which it is added. Calculate the number of grams of hydroxyapatite that will dissolve in 0.250L of a. neutral water. Calculate the number of grams of hydroxyapatite that will dissolve in 0.250L of b. water having a pH 5.5 Thus, the equilibrium concentration of ions is, =5x = 5x 1.01x104-5.05x104 Ca4 POj3x3x1.01x 10 -3.03x104 [Fx 1.01x10-4

The slightly soluble salt fluorapatite, Cas(PO4)3F, has a Ksp = 1 x 1031. It dissociates in water according to the following equation: Cas(PO4)3F(s) 5Ca2+ +3 PO43- + F Write the Ksp equation for this process: Ksp = 1. 2. Calculate the equilibrium concentrations of Ca2+, PO43- , and F. a. [Ca2] = b. [PO43-]= c. [F] = How many grams of fluorapatite will dissolve in 1L of water? 3. 4. The solubility of the related salt hydroxyapatite, Cas(PO4)30H (Ksp 1 x 10-29), is affected by the pH of the water to which it is added. Calculate the number of grams of hydroxyapatite that will dissolve in 0.250L of a. neutral water. Calculate the number of grams of hydroxyapatite that will dissolve in 0.250L of b. water having a pH 5.5 Thus, the equilibrium concentration of ions is, =5x = 5x 1.01x104-5.05x104 Ca4 POj3x3x1.01x 10 -3.03x104 [Fx 1.01x10-4

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter15: Equilibria Of Other Reaction Classes
Section: Chapter Questions
Problem 109E: The following question is taken from a Chemistry Advanced Placement Examination and is used with the...
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The slightly soluble salt fluorapatite, Cas(PO4)3F, has a Ksp = 1 x 1031. It dissociates in water according to the following equation: Cas(PO4)3F(s) 5Ca2+ +3 PO43- + F Write the Ksp equation for this process: Ksp = 1. 2. Calculate the equilibrium concentrations of Ca2+, PO43- , and F. a. [Ca2] = b. [PO43-]= c. [F] = How many grams of fluorapatite will dissolve in 1L of water? 3. 4. The solubility of the related salt hydroxyapatite, Cas(PO4)30H (Ksp 1 x 10-29), is affected by the pH of the water to which it is added. Calculate the number of grams of hydroxyapatite that will dissolve in 0.250L of a. neutral water. Calculate the number of grams of hydroxyapatite that will dissolve in 0.250L of b. water having a pH 5.5
Transcribed Image Text:The slightly soluble salt fluorapatite, Cas(PO4)3F, has a Ksp = 1 x 1031. It dissociates in water according to the following equation: Cas(PO4)3F(s) 5Ca2+ +3 PO43- + F Write the Ksp equation for this process: Ksp = 1. 2. Calculate the equilibrium concentrations of Ca2+, PO43- , and F. a. [Ca2] = b. [PO43-]= c. [F] = How many grams of fluorapatite will dissolve in 1L of water? 3. 4. The solubility of the related salt hydroxyapatite, Cas(PO4)30H (Ksp 1 x 10-29), is affected by the pH of the water to which it is added. Calculate the number of grams of hydroxyapatite that will dissolve in 0.250L of a. neutral water. Calculate the number of grams of hydroxyapatite that will dissolve in 0.250L of b. water having a pH 5.5
Thus, the equilibrium concentration of ions is, =5x = 5x 1.01x104-5.05x104 Ca4 POj3x3x1.01x 10 -3.03x104 [Fx 1.01x10-4
Transcribed Image Text:Thus, the equilibrium concentration of ions is, =5x = 5x 1.01x104-5.05x104 Ca4 POj3x3x1.01x 10 -3.03x104 [Fx 1.01x10-4
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