Spiropentane, shown on the left, reacts with Cl2 in the presence of light to furnish the two products shown on the right. Given that Cl2 is readily cleaved by light, provide a detailed step-by-step mechanism for the formation of the two products from the common intermediate shown in brackets, and also show the mechanism for the formation of the common intermediate from spiropentane. Use curved arrows to detail electron flow. Cl Cl2 + hv
Spiropentane, shown on the left, reacts with Cl2 in the presence of light to furnish the two products shown on the right. Given that Cl2 is readily cleaved by light, provide a detailed step-by-step mechanism for the formation of the two products from the common intermediate shown in brackets, and also show the mechanism for the formation of the common intermediate from spiropentane. Use curved arrows to detail electron flow. Cl Cl2 + hv
Chapter11: Reactions Of Alkyl Halides: Nucleophilic Substitutions And Eliminations
Section11.SE: Something Extra
Problem 74AP
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