Sr (s) + C(graphite) + 0,(g) → SrCO;(s) The information available is (1) Sr (s) + O2(g) → SrO (s) (2) SrO (s) + CO, (g) → SrCO, (s) (3) C(graphite) + 0, (g) → CO, (g) AH° = - 592 kJ %3D ΔΗ. - 234 kJ %3D AH° = ΔΗ - 394 kJ

Sr (s) + C(graphite) + 0,(g) → SrCO;(s) The information available is (1) Sr (s) + O2(g) → SrO (s) (2) SrO (s) + CO, (g) → SrCO, (s) (3) C(graphite) + 0, (g) → CO, (g) AH° = - 592 kJ %3D ΔΗ. - 234 kJ %3D AH° = ΔΗ - 394 kJ

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter2: The First Law Of Thermodynamics

Section: Chapter Questions

Problem 2.79E: The enthalpy of combustion of diamond is -395.4 kJ/mol. C s, dia O2 g CO2 g Determine the fH of C...

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Question

Sr (s) + C(graphite) + O,(g) → SrCO;(s)
The information available is
(1) Sr (s) + O2(g) → SrO (s)
(2) SrO (s) + CO, (g) → SrCO, (s)
(3) C(graphite) + O, (g) → CO, (g)
AH° = -592 kJ
ΔΗ.
- 234 kJ
AH° = - 394KJ

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