s sugar X a reducing or a non-reducing sugar?   Reducing, because one/both of the rings can open to expose a free aldehyde group Non-reducing, because one/both of the rings can open to expose a free aldehyde group Reducing, because neither of the rings can open to expose a free aldehyde group Non-reducing, because neither of the rings can open to expose a free aldehyde group Reducing, because one/both of the rings can open to expose a free ketone group Non-reducing, because one/both of the rings can open to expose a free ketone group Reducing, because neither of the rings can open to expose a free ketone group Non-reducing, because neither of the rings can open to expose a free ketone group Cannot be determined from the structure shown

Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter12: Chemical Bonding
Section: Chapter Questions
Problem 112AP
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sugar X a reducing or a non-reducing sugar?



 

Reducing, because one/both of the rings can open to expose a free aldehyde group

Non-reducing, because one/both of the rings can open to expose a free aldehyde group

Reducing, because neither of the rings can open to expose a free aldehyde group

Non-reducing, because neither of the rings can open to expose a free aldehyde group

Reducing, because one/both of the rings can open to expose a free ketone group

Non-reducing, because one/both of the rings can open to expose a free ketone group

Reducing, because neither of the rings can open to expose a free ketone group

Non-reducing, because neither of the rings can open to expose a free ketone group

Cannot be determined from the structure shown

Он он
H OH
но.
он
но
он
Он
sugar X
Transcribed Image Text:Он он H OH но. он но он Он sugar X
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