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standard deviations are given in the accompanying table. Treatment n x s Uneaten figs 20 2.80 0.30 Lizard dung 20 0.37 2.75 Bird dung 20 2.10 0.35 Hyrax dung 20| 1.85 0.26 n USE SALT (a) Construct the appropriate ANOVA table, and test the hypothesis that there is no difference between the means for the number of seeds germinating for the four treatments. (Use a = 0.05. Round your mean squares to three decimal places and F statistic to two decimal places.) Source of Variation Sum of Squares Mean df Square Treatments 3 26.25 8.750 83.93 Error 76 7.923 0.104 Total 79 34.173 Use technology to find the P-value. (Round your answer to four decimal places.) P-value = 0.0000

standard deviations are given in the accompanying table. Treatment n x s Uneaten figs 20 2.80 0.30 Lizard dung 20 0.37 2.75 Bird dung 20 2.10 0.35 Hyrax dung 20| 1.85 0.26 n USE SALT (a) Construct the appropriate ANOVA table, and test the hypothesis that there is no difference between the means for the number of seeds germinating for the four treatments. (Use a = 0.05. Round your mean squares to three decimal places and F statistic to two decimal places.) Source of Variation Sum of Squares Mean df Square Treatments 3 26.25 8.750 83.93 Error 76 7.923 0.104 Total 79 34.173 Use technology to find the P-value. (Round your answer to four decimal places.) P-value = 0.0000

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 1EQ: 1. Suppose that, in Example 2.27, 400 units of food A, 600 units of B, and 600 units of C are placed...
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Do lizards play a role in spreading plant seeds? Some research carried out in a country would suggest so. The researchers collected 400 seeds of this particular type of fig, 100 of which were from each treatment: lizard dung, bird dung, rock hyrax dung, and uneaten figs. They planted these seeds in batches of 5, and for each group of 5 they recorded how many of the seeds germinated. This resulted in 20 observations for each treatment. The treatment means and standard deviations are given in the accompanying table. Treatment n Uneaten figs 20 2.80 0.30 Lizard dung 20 2.75 0.37 Bird dung 20 2.10 0.35 Hyrax dung 20 1.85 0.26 n USE SALT (a) Construct the appropriate ANOVA table, and test the hypothesis that there is no difference between the means for the number of seeds germinating for the four treatments. (Use a = 0.05. Round your mean squares to three decimal places and F statistic to two decimal places.) Source of Sum of Mean df Variation Squares Square Treatments 3 26.25 8.750 83.93 Error 76 7.923 0.104 Total 79 34.173 Use technology to find the P-value. (Round your answer to four decimal places.) P-value = 0.0000
Transcribed Image Text:Do lizards play a role in spreading plant seeds? Some research carried out in a country would suggest so. The researchers collected 400 seeds of this particular type of fig, 100 of which were from each treatment: lizard dung, bird dung, rock hyrax dung, and uneaten figs. They planted these seeds in batches of 5, and for each group of 5 they recorded how many of the seeds germinated. This resulted in 20 observations for each treatment. The treatment means and standard deviations are given in the accompanying table. Treatment n Uneaten figs 20 2.80 0.30 Lizard dung 20 2.75 0.37 Bird dung 20 2.10 0.35 Hyrax dung 20 1.85 0.26 n USE SALT (a) Construct the appropriate ANOVA table, and test the hypothesis that there is no difference between the means for the number of seeds germinating for the four treatments. (Use a = 0.05. Round your mean squares to three decimal places and F statistic to two decimal places.) Source of Sum of Mean df Variation Squares Square Treatments 3 26.25 8.750 83.93 Error 76 7.923 0.104 Total 79 34.173 Use technology to find the P-value. (Round your answer to four decimal places.) P-value = 0.0000
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