State the expected ratio of ebony to non-ebony flies in the F2 generation. State the expected ratio of stubble to non-stubbly flies in the F2 generation.
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Table 1:
F1 ebony flies - 0
F1 non-ebony flies - 560
F1 stubble flies - 560
F1 non-stubble flies - 0
The researcher collects and crosses male and female flies from the F1 generation. In the resulting offspring, F2, there are both stubble and ebony flies.
State the expected ratio of ebony to non-ebony flies in the F2 generation.
State the expected ratio of stubble to non-stubbly flies in the F2 generation.
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- Table 1: F1 ebony flies - 0 F1 non-ebony flies - 560 F1 stubble flies - 560 F1 non-stubble flies - 0 The researcher collects and crosses male and female flies from the F1 generation. In the resulting offspring, F2, there are both stubble and ebony flies. Draw a Punnett Square to illustrate the F1 cross for the stubbly phenotype showing the individual gametes of each parent and the combination in the resulting offspring.The image attached shows a parental cross that is homozygous wild female x white male. F1 were intercrossed to produce the F2 generation as indicated below: Wild Female: 416 Wild Male: 192 White Female: 0 White Male: 192 Use the data provided to prepare a formal table for a Chi-square analysis.Cross Cross A Cross A Cross B Cross B Phenotype F1 generation F2 generation F1 generation F2 generation Male red eyes 132 150 0 99 Female red eyes 135 295 110 101 Male white eyes 0 147 105 93 Female white eyes 0 0 0 95 Using “+” to indicate the wildtype red-eyed allele and “w” to indicate the mutant white-eyed allele, state the genotypes of the following: Wildtype red-eyed and white-eyed parental flies from cross A and cross B. Males and females from the F1 generation flies from cross A and cross B Males and females, F2 generation flies from cross A and cross B.
- In a diploid plant species, an F1 with the genotype Mm Rr Ss is test crossed to a pure breeding recessive plant with the genotype mm rr ss. The offspring genotypes are as follows: Genotype Number Mm Rr Ss 687 Mm Rr ss 5 Mm rr Ss 68 Mm rr ss 196 mm Rr Ss 185 mm Rr ss 72 mm rr Ss 8 mm rr ss 679 Total 1900 1. What is the interference value for this data set?Solve the problem using punnett square. What is the probability that each of the following pairs of parents will produce the indicated offspring? AAbbCc X AaBBCc --> AaBbCc = AaBBCcDd X AaBbCcDD --> AaBBccDD =The phenotypic data below are the shoot lengths of 25 F1 and 25 F2 rice plants at seedling stage, produced from the cross of IR29 and Hasawi rice varieties. The mean lengths of the shoot from IR29 and Hasawi are 23.1 cm and 46.7 cm, respectively. Tabulate and plot the frequency distributions of the F1 and F2 generations. Use the formulas below in the computations. From each distribution calculate the mean, the variance, and the standard error of the mean. Round off answers to two decimal places. What is the main difference between F1 and F2 distributions?
- The mean, standard deviation, variances, and coefficient of variance of plant height from two rice plants (P1 and P2) and their progeny (F1 and F2) and a backcross generation (P1 x F1) are shown below. Explain the possible reasons for the observed differences in the sample means. Account for the differences in the sample means of P1 and P2. Similarly, account for the differences in the sample means of the F1 and F2. Compare the difference in the parental generations with that in the filial generations.The phenotypic data below are the shoot lengths of 25 F1 and 25 F2 rice plants atseedling stage, produced from the cross of IR29 and Hasawi rice varieties. The mean lengths of the shoot from IR29 and Hasawi are 23.1 cm and 46.7 cm, respectively. Tabulate and plot the frequency distributions of the F1 and F2 generations. From each distribution calculate the mean, the variance,and the standard error of the mean. What is the main difference between F1 and F2 distributions? Formulas needed:Range (R) = maximum – minimum (Use the same no. of decimal places as original data.)No. of phenotypic classes (K) = 1 + 3.3logn (Round up answer to an integer. Number may still be increased or decreased as needed.)n = total no. of valuesClass interval (CI) = R/K (Use the same no. of decimal places as original data.)Please solve step by step THANKS! A researcher when studying insects of the genus Protenor, crossed females with normal wings and short antennae, with males with short wings and long antennae. In the first generation, he found that all insects had normal wings and long antennae; Therefore, when obtaining the second generation of a count of 460 insects, 50 presented short wings and short antennae; 135 with normal wings and short antennae; 165 with short wings and long antennae; and 465 with normal wings and long antennae. According to the information, determine:a) The genotype of the F1 and the parentsb) How many pairs of genes are involved in the crossc) How is the inheritance of these characters,d) Obtain the genotypic and phenotypic relationshipe) If the test cross is made, what genotypic and phenotypic relationship is expected
- In your F2 light treatment vial, you observe the following data: 5 white-eyed males, 18 wild-type males, 7 white-eyed females, and 10 wild-type females. What is the white-eyed allele frequency in this generation? Leave your answer as a decimal. Give the explanation also.You may insert a hand-drawn diagram of your map, but the rest of the assignment must be fully typed. The data set attached presents the results of a testcross using female flies heterozygous for three traits and male flies, which are homozygous recessive. For simplicity, mutant alleles are shown with letters a, b, and c and wildtype alleles are indicated by a “+” symbol. For this part of the report do the following in order: a) Determine the gene order (which gene is in the middle?)d) Construct a genetic map for the three genes, including the map distances between them. Clearly indicate the logic you followed and show all your calculations. Include the full distance calculations for the two most distanced genes (do not just add the other 2 distances). Ensure the work is neat and clear and does not contain spelling or grammatical errors so that it is understandable.In a diploid plant species, an F1 with the genotype Mm Rr Ss is test crossed to a pure breeding recessive plant with the genotype mm rr ss. The offspring genotypes are as follows: Genotype Number Mm Rr Ss 687 Mm Rr ss 5 Mm rr Ss 68 Mm rr ss 196 mm Rr Ss 185 mm Rr ss 72 mm rr Ss 8 mm rr ss 679 Total 1900 1. What is the gene order of these linked genes?