step 6 Trial Windmilling Stopped82.375.8123456789101112131473.468.974.171.774.22363.564.460.979.574.576.570.372.715 64.216 67.517 71.218 75.619 73.171.320 77.421 7722 77.87724 72.32569.226 63.927 70.3<75.700:2271.768.874.27868.590.681.972.975.777.6174.382.581.172.377.782.679.582.379.579.773.47674.279AA✰ webassign.net Step 3: The author indicated that one of the trials was unusual. In this trial, one flight experienced anupdraft of wind that caused an unusually long time to descend 800 ft, making the difference for this pairquite a bit larger than the other pairs. As such, it is reasonable to remove trial number 14 from the data setbecause the condition of calm winds was not maintained.Delete trial number 14 from the data set. Create and upload a new boxplot of the differences. (Submit a filewith a maximum size of 1 MB.)Choose File no file selectedThis answer has not been graded yet.Does this new boxplot indicate that it is reasonable to assume the distribution of differences for thepopulation of differences in time to descend 800 ft at 60 knots with calm winds is normal?Yes, the plot is approximately symmetric and there are no outliers.No, the plot is approximately symmetric and there are no outliers.Yes, the plot is not approximately symmetric and there is at least one outlier.No, the plot is not approximately symmetric and there is at least one outlier.Step 4: Because all conditions are met, it is appropriate to use the paired samples t test to analyze thesedata. Run the paired samples t test on this data set to determine whether there is a difference in time todescend 800 ft when the propeller is windmilling versus when the propeller is stopped and report the resultsbelow. Set the significance level at a = 0.05.The hypothesis statement isно на0Ha: Md #=Degrees of freedom for this test: df = 25Mean of the differences (rounded to two decimal places): xd=t =Standard error of the mean (rounded to two decimal places):0хо-наCompute the test statistic using the rounded values above. Report the test statistic. (Round your answer totwo decimal places.)5.92sd = 5.49√nThe P-value for this test statistic (rounded to two decimal places) is 0.0011.08Step 5: Because the P-value is lessleads to a decision of rejectîsecondsthan the significance level, a = 0.05, this hypothesis testthe null hypothesis. There isconvincing evidenceîthat there is a difference in time to descend 800 ft when the propeller is windmilling versus when thepropeller is stopped.Step 6: Create a 98% confidence interval for the difference in time to descend 800 ft.The t critical value for this confidence interval based on 25 degrees of freedom and rounded to three decimalplaces is 2.485Lower limit (rounded to two decimal places) isUpper limit (rounded to two decimal places) isBased on this analysis, we are 98% confident that the actual difference in time to descend800 ft is somewhere between 10X andseconds. Because both endpoints of theinterval are positive, this indicates that the mean time to descend 800 ft when the propeller is stopped îis greater than when the propeller is windmilling ✔ . In conclusion, if a single-propeller-drivenairplane experiences engine failure, there is a greater likelihood of longer glide expected if the propeller isforced to stop

Given that: Confidence level=98% Sample mean of differences, x¯d=5.92 Standard error of mean,…

Step 6: Create a 98% confidence interval for the difference in time to descend 800 ft. The t critical value for this confidence interval based on 25 degrees of freedom and rounded to three decimal places is 2.485 Lower limit (rounded to two decimal places) is Upper limit (rounded to two decimal places) is Based on this analysis, we are 98 % confident that the actual difference in time to descend 800 ft is somewhere between 10 X and seconds. Because both endpoints of the interval are positive, this indicates that the mean time to descend 800 ft when the propeller is stopped ✔ is greater than when the propeller is windmilling ✔ . In conclusion, if a single-propeller-driven airplane experiences engine failure, there is a greater likelihood of longer glide expected if the propeller is forced to stop

Step 6: Create a 98% confidence interval for the difference in time to descend 800 ft. The t critical value for this confidence interval based on 25 degrees of freedom and rounded to three decimal places is 2.485 Lower limit (rounded to two decimal places) is Upper limit (rounded to two decimal places) is Based on this analysis, we are 98 % confident that the actual difference in time to descend 800 ft is somewhere between 10 X and seconds. Because both endpoints of the interval are positive, this indicates that the mean time to descend 800 ft when the propeller is stopped ✔ is greater than when the propeller is windmilling ✔ . In conclusion, if a single-propeller-driven airplane experiences engine failure, there is a greater likelihood of longer glide expected if the propeller is forced to stop

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter8: Sequences, Series, And Probability

Section8.7: Probability

Problem 57E: What is an experiment? Give two examples.

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What is an experiment? Give two examples.
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4. Failure to meet payments on student loans guaranteed by the United States (U.S.) government has been a major problem for both banks and the government. Approximately 50% of all student loans guaranteed by the government are in default. A random sample of 350 loans to college students in one region of the U.S. indicates that 147 loans are in default. a) Do the data indicate that the proportion of student loans in default in this area of the country differs from the proportion of all student loans in the U.S. that are in default? Use α = 0.01. (ii) The test statistic for the above problem is
4. Failure to meet payments on student loans guaranteed by the United States (U.S.) government has been a major problem for both banks and the government. Approximately 50% of all student loans guaranteed by the government are in default. A random sample of 350 loans to college students in one region of the U.S. indicates that 147 loans are in default. a) Do the data indicate that the proportion of student loans in default in this area of the country differs from the proportion of all student loans in the U.S. that are in default? Use α = 0.01. (i) The conclusion for the above problem is