STION 12 ider the Double Linked List that is given below, where each box represents a 'node' type with two fields: integer data and a node type reference 'next' that points to the node in the list. Write an algorithm to count all nodes that contains an odd number. O Write an algorithm to print all nodes that contain an even number in the reverse direction of the list. + null tail T F Paragraph v Arial 3 (12pt) Mashups HTHL ESS
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- C++ question 1.) Write an iterative routine that will take a string, go through each character of the string and enqueue the character if it is a punctuation (.,?!), else toss the character. When end of string is reached, then dequeue the characters, count how many punctuations are there, then print the count. 2.) Write a routine that would receive a pointer to the top of the linked list that has an integer for each node. Change all odd integers to even by adding one. But count the numbers you changed and print the count.8.14 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp: #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData()…8.14 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp: #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData()…
- 8.14 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData()…8.14 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData()…Assume a linked list contains following integers: 5, 2, 4, 6, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a=0; while(curNode!=NULL){ a+=curNode->getItem(); curNode=curNode->getNext(); if(curNode!=NULL) curNode=curNode->getNext(); } A.32 B.43 C.19 D.18
- int F(node<int>&p){int c=0; while(p!=0){p=p->next; c++; } return c;} This function is a. return the number of items in the linked list b. return the number of items in a linked list and destroy the linked list c. None of these d. destroy the list and free all allocated nodesAssume a linked list contains following integers: 2, 2, 4, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode; curNode=new Node<int>(10,head); head=curNode; int a; while(curNode!=NULL){ a+=curNode->getItem(); curNode=curNode->getNext(); } A.49 B.39 C.7 D.15Assume a linked list contains following integers: 5, 2, 4, 6, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a=0; curNode->setNext(NULL); while(curNode!=NULL){ a+=curNode->getItem(); curNode=curNode->getNext(); } A.5 B.2 C.43 D.38
- Which of the following statement is not true about the doubly linked list? A. We can traverse in both the directions. B. It requires extra space C. Implementation of doubly linked list is easier than the singly linked list D. It stores the addresses of the next and the previous nodeComplete the following function where a node is perculated through a MaxHeap when given the value of the parent node (through the use of a linked list) void BinMaxHeap::percolateUp(BHNode *p) { }Think about the following example: A computer program builds and modifies a linked list like follows:Normally, the program would keep tabs on two unique nodes, which are as follows: An explanation of how to use the null reference in the linked list's node in two common circumstances