7.305.904.50Stress Lev3.101.70Opoxഒന്നും00O 000000 0O DO XD CODO O 00000.10 0.10 0.30#obs R^2 const a std-err a t-stat a315 0.047 2.626 0.105 25.0700000.105 25.070 00 0315 0.0470 0 0 ОфB BBB O ∞0-aCODO OOO O0.50 0.70 0.90 1.10Percent_trp-value a slope b std-err b0Question 3: What is the intercept and what is the slope?t-stat b p-value b0.00000.00002.626-0.933 0.236 -3.948000-0.933 0.236 -3.948Chow test for sel/unsel regression subsets: can't computeThe independent variable is Percent an the dependent variable is StressQuestion 2: Are the two variables positively correlated or negatively?

Question 2 Here as shown in the graph the stress level is decreasing with the increase in the…

Answered: Stress_Lev 7.30 5.90 4.50 3.10 1.70 .30…

Stress_Lev 7.30 5.90 4.50 3.10 1.70 .30 pox O 00 xoo .. ∞ 。。 O O O XXO XED ∞∞∞∞∞∞ . നാൽ സ -0.10 0.10 0.30 COMO OOOO 0 000XXO CO 0.50 0.70 0.90 1.10 Percent tr

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

يخرج الهواء من فوهة معزولة عند 27 درجة مئوية و 100 كيلو باسكال و 150 (م / ث). إذا كانت الكفاءة الحرارية للفوهة 90٪ ، ارسم مخطط Ts لهذه العملية وحدد درجة حرارة المدخل والضغط (7، & P)؟ خذ (Cp = 1.005 و k = 1.4).
Linearize the model ? = ? ? ?^(?? )and solve for the coefficients by hand using the following data x 0.1 0.2 0.4 0.6 0.9 1.3 1.5 1.7 1.8 y 0.75 1.25 1.45 1.25 0.85 0.55 0.35 0.28 0.18
Please solve part B please!! thank youu will rate your answer!ᴘᴀʀᴛ ᴀ.ᴀ ᴋɴᴜᴄᴋʟᴇ ᴊᴏɪɴᴛ ɪꜱ ᴛᴏ ʙᴇ ᴀxɪᴀʟʟʏ ʟᴏᴀᴅᴇᴅ ᴡɪᴛʜ ᴀ ᴛᴇɴꜱɪʟᴇ ʟᴏᴀᴅ ꜰ. ᴛʜᴇ ᴀꜱꜱᴇᴍʙʟʏ ᴏꜰ ᴘᴀʀᴛꜱ ᴀɴᴅ ᴛʜᴇɪʀ ᴠᴀʀɪᴀʙʟᴇᴅɪᴍᴇɴꜱɪᴏɴꜱ ᴀʀᴇ ꜱʜᴏᴡɴ ɪɴ ᴛʜᴇ ꜰɪɢᴜʀᴇ ʙᴇʟᴏᴡ. ᴡʀɪᴛᴇ ᴛʜᴇ ꜱᴛʀᴇꜱꜱ ᴇQᴜᴀᴛɪᴏɴ ᴀᴛ ᴇᴀᴄʜ ᴏꜰ ᴛʜᴇ ᴘᴏꜱꜱɪʙʟᴇ ʟᴏᴄᴀᴛɪᴏɴꜱ ᴏꜰ ꜰᴀɪʟᴜʀᴇ. ɪᴅᴇɴᴛɪꜰʏ ᴇᴀᴄʜ ꜱᴛʀᴇꜱꜱ ᴀɴᴅ ᴡʀɪᴛᴇ ɪᴛꜱ ᴇQᴜᴀᴛɪᴏɴ ɪɴ ᴛᴇʀᴍꜱ ᴏꜰ ᴛʜᴇ ʟᴏᴀᴅ ꜰ, ᴀɴᴅ ᴛʜᴇ ɢɪᴠᴇɴ ᴅɪᴍᴇɴꜱɪᴏɴꜱ ᴀ, ʙ, ᴄ, ᴅ, ᴋ, ᴍ ᴀɴᴅ ɴ. (ᴇxᴀᴍᴘʟᴇ: ᴛᴇɴꜱɪʟᴇ ꜱᴛʀᴇꜱꜱ ᴀᴛ ᴛʜᴇ ʀᴏᴅ ᴏꜰ ᴛʜᴇ ᴋɴᴜᴄᴋʟᴇ ᴊᴏɪɴᴛ: ꜱᴛ = 4ꜰ/Πᴅ2). ᴅᴏɴ’ᴛ ᴜꜱᴇ ᴠᴀʀɪᴀʙʟᴇꜱ ᴛʜᴀᴛ ᴀʀᴇ ɴᴏᴛ ᴅᴇꜰɪɴᴇᴅ ɪɴ ᴛʜᴇ ᴊᴏɪɴᴛ ᴅᴇꜱᴄʀɪʙᴇᴅ ʙᴇʟᴏᴡ. ꜱᴜᴘᴘᴏʀᴛ ᴇᴀᴄʜ ᴏꜰ ᴛʜᴇ ꜱᴛʀᴇꜱꜱ ᴇQᴜᴀᴛɪᴏɴꜱ ʙʏ ᴍᴇᴀɴꜱ ᴏꜰ ᴀɴ ɪꜱᴏᴍᴇᴛʀɪᴄ ᴅʀᴀᴡɪɴɢ ɪɴᴅɪᴄᴀᴛɪɴɢ ᴛʜᴇ ᴘᴀʀᴛ ᴀɴᴅ ɪᴛꜱ ᴅɪᴍᴇɴꜱɪᴏɴꜱ ᴛʜᴀᴛ ᴍɪɢʜᴛ ʜᴀᴠᴇ ꜰᴀɪʟᴇᴅ ᴅᴜᴇ ᴛᴏ ᴏᴠᴇʀꜱᴛʀᴇꜱꜱɪɴɢ. ꜰᴏʀ ᴛʜᴇ ʙᴇɴᴅɪɴɢ ꜱᴛʀᴇꜱꜱ ɪɴ ᴛʜᴇ ᴘɪɴ, ᴄᴏɴꜱɪᴅᴇʀ ᴛʜᴇ ʟᴏᴀᴅꜱ ᴛᴏ ʙᴇ ᴜɴɪꜰᴏʀᴍʟʏ ᴅɪꜱᴛʀɪʙᴜᴛᴇᴅ ᴀᴛ ᴛʜᴇ ᴄᴇɴᴛᴇʀ ᴏꜰ ᴛʜᴇ ᴄᴏᴛᴛᴇʀ ᴀɴᴅ ᴜɴɪꜰᴏʀᴍʟʏ ᴠᴀʀʏɪɴɢ ᴀᴛ ᴛʜᴇ ᴋɴᴜᴄᴋʟᴇ ᴇɴᴅ. ɴᴇɢʟᴇᴄᴛ ᴛʜᴇ ᴘʀᴇꜱᴇɴᴛ ᴏꜰ ᴛʜᴇ ꜰɪʟʟᴇᴛꜱ ɪɴ ᴄᴏɴꜱɪᴅᴇʀɪɴɢ ᴛʜᴇ ᴅɪᴍᴇɴꜱɪᴏɴꜱᴘᴀʀᴛ ʙ.ᴜꜱɪɴɢ ᴛʜᴇ ꜱᴛʀᴇꜱꜱ ᴇQᴜᴀᴛɪᴏɴꜱ ꜰᴏʀᴍᴇᴅ ɪɴ ᴘᴀʀᴛ ᴀ, ᴅᴇꜱɪɢɴ ᴛʜᴇ ᴊᴏɪɴᴛ ʙʏ ꜱᴘᴇᴄɪꜰʏɪɴɢ…
ᴀ ᴘᴜᴍᴘ ᴡɪᴛʜ ᴀ 400 ᴍᴍ ᴅɪᴀᴍᴇᴛᴇʀ ꜱᴜᴄᴛɪᴏɴ ᴘɪᴘᴇ ᴀɴᴅ ᴀ 350 ᴍᴍ ᴅɪᴀᴍᴇᴛᴇʀ ɪꜱ ᴛᴏ ᴅᴇʟɪᴠᴇʀ 20,000 ʟ/ᴍɪɴ ᴏꜰ 15.6ᴅᴇɢ ᴄ ᴡᴀᴛᴇʀ. ᴄᴀʟᴄᴜʟᴀᴛᴇ ᴛʜᴇ ᴘᴜᴍᴘ ʜᴇᴀᴅ ɪɴ ᴍᴇᴛᴇʀꜱ ɪꜰ ꜱᴜᴄᴛɪᴏɴ ɢᴀɢᴇ ɪꜱ 7.5 ᴄᴍ ʙᴇʟᴏᴡ ᴘᴜᴍᴘ ᴄᴇɴᴛᴇʀʟɪɴᴇ ᴀɴᴅ ʀᴇᴀᴅꜱ 127 ᴍᴍʜɢ ᴠᴀᴄᴜᴜᴍ ᴀɴᴅ ᴅɪꜱᴄʜᴀʀɢᴇ ɢᴀɢᴇ ɪꜱ 45 ᴄᴍ ᴀʙᴏᴠᴇ ᴛʜᴇ ᴘᴜᴍᴘ ᴄᴇɴᴛᴇʀʟɪɴᴇ ᴀɴᴅ ʀᴇᴀᴅꜱ 75 ᴋᴘᴀ ɴᴏᴛᴇ, ᴢ ɪꜱ ᴀʟꜱᴏ ᴛʜᴇ ᴅɪꜱᴛᴀɴᴄᴇ ᴏꜰ ᴘʀᴇꜱꜱᴜʀᴇ ɢᴀɢᴇ ᴛᴏ ᴛʜᴇ ᴘᴜᴍᴘ. ᴍɪɴᴅ ᴛʜᴇ ᴜɴɪᴛꜱ.
y (mm) Po (Pa) 0 101325 0.03 101325.153 0.09 101326.378 0.15 101328.828 0.21 101332.503 0.27 101337.403 0.6 101348.887 1.55 101358.839 2.5 101364.528 3.45 101368.634 4.4 101371.895 5.35 101374.629 6.3 101377.002 7.25 101379.115 8.2 101381.03 9.15 101382.793 10.1 101384.435 11.05 101385.978 12 101387.441 12 101387.441 19.091 101396.814 26.182 101404.815 33.273 101412.065 40.364 101418.55 47.455 101424.037 54.545 101428.261 61.636 101432.34 68.727 101432.34 75.818 101432.34 82.909 101432.34 90 101432.34
Forecast sales for the 7th period. For leveling, use exponential smoothing 0.20 and moving average 3 for averaging; and linear and exponential functions for trend data. Assume an initial exponential forecast of 60 units in period 2 if you decide to use it (i.e., no forecast for period 1). Period Demand 1 67 2 72 3 68 4 20 5 70 6 66 7 68
Interpret the following results in a correlation analysis:a. r = 0.27, n =100b. r=0.27,n=16c. r=-0.75,n=16d. r = 0.02, n =100
A tape 30m long of standard length a 29Celcius was used to measure a line the mean temperature during measurement was 15Celcius, the measured distance was 221.65 m, the following being the slopes:1 degree 10’ for 60 m2 degree 20’ for 30 m5 degree 18’ for 30 m4 degree 40’ for 12 m1 degree 30’ for 30 m3 degree 48’ for 30 m7 degree 20’ for 18 m1 degree 20’ for 11.65 mFind the true length of the line if the coefficient of expansion is 116x10^-7 per 1Celcius
Based in the table 1. (need to answer question 4,5,6)1) Develop a best-fit equation for the relationship between stress and strain. Employ Naïve–Gauss elimination method whenever necessary.S=___28.65___+___294.43___e + ___235.22____e2 2) Determine the coefficient of determination for the equation. R2 =___0.636____ 3) Calculate the stress value to the most accurate value at strain value 0.53.s = ___250.76____Pa4) The yield point is the point on a stress–strain curve that indicates the limit of elastic behaviour and the beginning of plastic behavior. In this case, the yield point occurs at a stress value of 80. Determine the corresponding strain value at the yield point. In any relevant method, use a stopping criterion of 0.05% e =_______ 5) The ultimate strength is the maximum point on the stress–strain curve. This corresponds to the maximum stress that can be sustained by a structure in tension. Compute the ultimate strength point of the polymeric material (strain value that gives…
An electrical contractor’s records during the last five weeks indicate the number of job requests: Week 1 2 3 4 5 Jobs 20 22 18 21 22 Predict the number of requests for week 6 using each of this method:c. Exponential smoothing with α = .30; use 20 for week 2 forecast
ʏᴏᴜ ᴀʀᴇ ɪɴꜱᴛʀᴜᴄᴛᴇᴅ ʙʏ ᴛʜᴇ ᴘʟᴀɴᴛ ᴏᴘᴇʀᴀᴛɪᴏɴꜱ ᴍᴀɴᴀɢᴇʀ ᴛᴏ ɪɴꜱᴛᴀʟʟ ᴀ ᴘᴜᴍᴘ ᴛᴏ ʟɪꜰᴛ 30ʟ/ꜱ ᴏꜰ ᴡᴀᴛᴇʀ ᴀᴛ 22ᴅᴇɢᴄ ꜰʀᴏᴍ ᴀ ꜱᴜᴍᴘ ᴛᴏ ᴀ ᴛᴀɴᴋ. ᴛʜᴇ ᴛᴀɴᴋ ᴘʀᴇꜱꜱᴜʀᴇ ɪꜱ 200ᴋᴘᴀɢ. ᴛʜᴇ ᴡᴀᴛᴇʀ ʟᴇᴠᴇʟ ɪɴ ᴛʜᴇ ᴛᴀɴᴋ ɪꜱ 20ᴍ ᴀʙᴏᴠᴇ ᴛʜᴇ ᴘᴜᴍᴘ ᴄᴇɴᴛᴇʀʟɪɴᴇ ᴀɴᴅ ᴛʜᴇ ᴘᴜᴍᴘ ɪꜱ 4ᴍ ᴀʙᴏᴠᴇ ᴛʜᴇ ᴡᴀᴛᴇʀ ʟᴇᴠᴇʟ ɪɴ ᴛʜᴇ ꜱᴜᴍᴘ. ᴛʜᴇ ꜱᴜᴄᴛɪᴏɴ ᴘɪᴘᴇ ɪꜱ 100ᴍᴍ ɪɴ ᴅɪᴀᴍᴇᴛᴇʀ, 7ᴍ ʟᴏɴɢ, ᴀɴᴅ ᴄᴏɴᴛᴀɪɴꜱ 2 ᴇʟʙᴏᴡꜱ ᴀɴᴅ ᴀ ꜰᴏᴏᴛ ᴠᴀʟᴠᴇ. ᴡʜɪʟᴇ ᴛʜᴇ ᴅɪꜱᴄʜᴀʀɢᴇ ᴘɪᴘᴇ ᴛᴏ ᴛʜᴇ ᴛᴀɴᴋ ʜᴀꜱ 75ᴍᴍ ᴅɪᴀᴍᴇᴛᴇʀ ᴀɴᴅ ɪꜱ 120ᴍ ʟᴏɴɢ ᴡɪᴛʜ 5ᴘᴄꜱ 90ᴅᴇɢ ᴇʟʙᴏᴡ, ᴀ ᴄʜᴇᴄᴋ ᴠᴀʟᴠᴇ ᴀɴᴅ ᴀ ɢᴀᴛᴇ ᴠᴀʟᴠᴇ. ᴛʜᴇ ʜᴇᴀᴅ ʟᴏꜱꜱ ꜰʀᴏᴍ ᴛʜᴇ ꜱᴜᴄᴛɪᴏɴ ʟɪɴᴇ ᴀɴᴅ ᴅɪꜱᴄʜᴀʀɢᴇ ʟɪɴᴇ ɪꜱ 5 ᴛɪᴍᴇꜱ ᴛʜᴇ ꜱᴜᴄᴛɪᴏɴ ᴠᴇʟᴏᴄɪᴛʏ ʜᴇᴀᴅ ᴀɴᴅ 15 ᴛɪᴍᴇꜱ ᴛʜᴇ ᴅɪꜱᴄʜᴀʀɢᴇ ᴠᴇʟᴏᴄɪᴛʏ ��ᴇᴀᴅ, ʀᴇꜱᴘᴇᴄᴛɪᴠᴇʟʏ. ꜰᴏʀ ᴀ ᴍᴇᴄʜᴀɴɪᴄᴀʟ ᴇꜰꜰɪᴄɪᴇɴᴄʏ ᴏꜰ 80%. ᴅᴇᴛᴇʀᴍɪɴᴇ ᴛʜᴇ ʀᴇQᴜɪʀᴇᴅ ᴍᴏᴛᴏʀ ᴏᴜᴛᴘᴜᴛ ᴘᴏᴡᴇʀ (ᴋᴡ).
Using trapezoidal rule integration with 2 equal sized sub-intervals, find the area under the curve defined by the polynomial y = 0.04x5 + 0.5x3 + 38 between limits of 4.7 and 11.0. Give your answer to a precision of at least 3 significant figures.