Sulfur containing compound weighing 4.8670 grams was digested and purified to form H,SO¸. A 25.00-mL of 0.0090 M NaOH was added to the collected H SO , and the excess base was then back titrated with 13. 45 mL of 0.0100 M HCI. Calculate the sulfur content in the sample parts per million. This problem involves back titration. Write the two chemical equations involved in the analysis. Identify the analyte, “bridging" reagent and titrant. Solve for the mole of the analyte using the titration values and the stoich relationships. One mole of H,so, is equal to one mole of sulfur in the sample. Solve for the mass of S then ppm S.

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Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 132IP: A 10.00-g sample of the ionic compound NaA, where A is the anion of a weak acid, was dissolved in...
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Sulfur containing compound weighing 4.8670 grams was digested and
purified to form H,SO̟. A 25.00-mL of 0.0090 M NaOH was added to the
collected H,So, and the excess base was then back titrated with 13. 45 mL
of 0.0100 M HCI. Calculate the sulfur content in the sample parts per
million.
This problem involves back titration. Write the two chemical equations involved in
the analysis. Identify the analyte, "bridging" reagent and titrant. Solve for the mole
of the analyte using the titration values and the stoich relationships. One mole of
H,So, is equal to one mole of sulfur in the sample. Solve for the mass of S then
ppm S.
Transcribed Image Text:Sulfur containing compound weighing 4.8670 grams was digested and purified to form H,SO̟. A 25.00-mL of 0.0090 M NaOH was added to the collected H,So, and the excess base was then back titrated with 13. 45 mL of 0.0100 M HCI. Calculate the sulfur content in the sample parts per million. This problem involves back titration. Write the two chemical equations involved in the analysis. Identify the analyte, "bridging" reagent and titrant. Solve for the mole of the analyte using the titration values and the stoich relationships. One mole of H,So, is equal to one mole of sulfur in the sample. Solve for the mass of S then ppm S.
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