Suppose a 500. mL flask is filled with 1.8 mol of CH,, 0.60 mol of H,S and 0.10 mol of H,. This reaction becomes possible: CH,(2) + 2H,S(g) → Cs,(e) +4H,(2) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reacti equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of CS,. You can leave out the M symbol for molarity. CH, H,S cs, H, initial 3.6 1.2 5 ? change equilibrium

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter3: Mass Relations In Chemistry; Stoichiometry
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Problem 17QAP: What is the molarity of each ion present in aqueous solutions of the following compounds prepared by...
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Suppose a 500. mL flask is filled with 1.8 mol of CH,, 0.60 mol of H,S and 0.10 mol of H,. This reaction becomes possible:
CH,(2) + 2H,S(g) → Cs,(g) +4H,(2)
Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reactio.
equilibrium molarity of each compound after the reaction has come to equilibrium.
Use x to stand for the unknown change in the molarity of CS,. You can leave out the M symbol for molarity.
CH,
H,S
Cs,
H,
initial
3.6
12
2
change
equilibrium
Explanation
Check
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Transcribed Image Text:Suppose a 500. mL flask is filled with 1.8 mol of CH,, 0.60 mol of H,S and 0.10 mol of H,. This reaction becomes possible: CH,(2) + 2H,S(g) → Cs,(g) +4H,(2) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reactio. equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of CS,. You can leave out the M symbol for molarity. CH, H,S Cs, H, initial 3.6 12 2 change equilibrium Explanation Check 2022 McGraw H LLC A ights eser O Type here to search SPOG URAL SUs ZenBook D Alt Alt
Expert Solution
Step 1

The equilibrium reaction given is,

=> CH4 (g)+ 2 H2S(g)  CS2 (g)+ 4 H2 (g)

Given: Volume of flask = 0.500 L                                                        (Since 1 L = 1000 mL)

Moles of CH4 initially = 1.8 mol.

Moles of H2S initially = 0.60 mol.

Moles of H2 initially = 0.10 mol.

And the change in molarity of CS2 = x.

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