Suppose an electron (q = - e = -1.6 × 10¬19 C,m=9.1 × 10¬3' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve fa the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K = -U 1 Since K= mv and using the formula for potential energy above, we arrive at an equation for speed: v= ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=

Suppose an electron (q = - e = -1.6 × 10¬19 C,m=9.1 × 10¬3' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve fa the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K = -U 1 Since K= mv and using the formula for potential energy above, we arrive at an equation for speed: v= ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter39: Relativity

Section: Chapter Questions

Problem 39.66AP

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