Suppose an electron (q= -e  = -1.6 x 10^-19 C, m = 9.1 x 10^-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. Use the template in the attached photo to solve for the problem.

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 22P
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Suppose an electron (q= -e  = -1.6 x 10^-19 C, m = 9.1 x 10^-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. Use the template in the attached photo to solve for the problem. 

potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant
figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:
U =
Assuming all potential energy U is converted to kinetic energy K,
K+U = 0
K= -U
1
Since K= mv and using the formula for potential energy above, we arrive at an equation for speed:
v =(
1/2
Plugging in values, the value of the electron's speed is:
x 107 m/s
V=
Transcribed Image Text:potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K= -U 1 Since K= mv and using the formula for potential energy above, we arrive at an equation for speed: v =( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=
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