Suppose that in Sample Problem 7.7, the orientation of the second and third filters are interchanged. Find the intensity of light emerging from each filter.

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Chapter37: Diffraction Patterns And Polarization
Section: Chapter Questions
Problem 32P: An unpolarized beam of light is incident on a stack of ideal polarizing filters. The axis of the...
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PLEASE ANSWER PRACTICE EXERCISE 7.7 GIVEN REQUIRED EQUATION SOLUTION ANSWER THANK YOU!
Assuming that the first polarizer is an ideal polarizer,
filters are 30° and 75° to that of the first, respectively.
Sample Problem 7.7
Three polarizing filters are arranged in such a way
b=12 W/m?
75
Gnd the intensity of light emerging from each filter if
its original intensity is 12 W/m².
O3 =75°-30° =45° 1,=12 W/m?
Given: 0,=30°
Solution:
I,
(12 W/m²)
I, after passing through the first filter =
2
= 6 W/m?
2
m cos o = 1, cos*o, = (6 W/m³)cos²30° = 4.5 W/m²
1, after passing through the third filter = Imax cos o = 1, cos o, = (4.5 W/m³)cos²45° = 2.25 W/m?
1, after passing through the second filter =
I.
Practice Exercise 7.7
Suppose that in Sample Problem 7.7, the orientation of the second and third filters are
interchanged. Find the intensity of light emerging from each filter.
Polarized light may also be produced at a particular angle of
incidence called Brewster's angle or polarizing angle. At Brewster's angle,
the reflected ray is almost completely polarized and is perpendicular
to the refracted ray (figure 7-13). Using Snell's law and taking
n, = Nair=1.00 and n2=n (of the reflecting surface), the Brewster's angle
is given by
0,
Fig. 7-12. At the polarizing angie
tan 0,=
Eg. (7.14) 8, the reflected and refracted roos
are perpendicular to each other.
=n.
Transcribed Image Text:Assuming that the first polarizer is an ideal polarizer, filters are 30° and 75° to that of the first, respectively. Sample Problem 7.7 Three polarizing filters are arranged in such a way b=12 W/m? 75 Gnd the intensity of light emerging from each filter if its original intensity is 12 W/m². O3 =75°-30° =45° 1,=12 W/m? Given: 0,=30° Solution: I, (12 W/m²) I, after passing through the first filter = 2 = 6 W/m? 2 m cos o = 1, cos*o, = (6 W/m³)cos²30° = 4.5 W/m² 1, after passing through the third filter = Imax cos o = 1, cos o, = (4.5 W/m³)cos²45° = 2.25 W/m? 1, after passing through the second filter = I. Practice Exercise 7.7 Suppose that in Sample Problem 7.7, the orientation of the second and third filters are interchanged. Find the intensity of light emerging from each filter. Polarized light may also be produced at a particular angle of incidence called Brewster's angle or polarizing angle. At Brewster's angle, the reflected ray is almost completely polarized and is perpendicular to the refracted ray (figure 7-13). Using Snell's law and taking n, = Nair=1.00 and n2=n (of the reflecting surface), the Brewster's angle is given by 0, Fig. 7-12. At the polarizing angie tan 0,= Eg. (7.14) 8, the reflected and refracted roos are perpendicular to each other. =n.
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