Suppose that in the RLC circuit below, a voltage of Vin = 6 sin(5t) is applied at t = 0, when Vc(0) = 2, V¿(0) = –1. 20 N 2 H Vin (+ .02 F Solve for the voltage across the capacitor, V = Vc(t). Use undeter- mined coefficients.

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Suppose that in the RLC circuit below, a voltage of Vin = 6 sin(5t) is applied at t = 0,
when Vc (0) = 2, V¿(0) = –1.
|
20 Ω
2 H
Vin
.02 F
Solve for the voltage across the capacitor, V = Vc(t). Use undeter-
mined coefficients.
Transcribed Image Text:Suppose that in the RLC circuit below, a voltage of Vin = 6 sin(5t) is applied at t = 0, when Vc (0) = 2, V¿(0) = –1. | 20 Ω 2 H Vin .02 F Solve for the voltage across the capacitor, V = Vc(t). Use undeter- mined coefficients.
Sketch both the steady state solution Vs(t) and the solution to the IVP
V (t), graphed
on the same axis.
Transcribed Image Text:Sketch both the steady state solution Vs(t) and the solution to the IVP V (t), graphed on the same axis.
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