Suppose that the following is to be tested: Ho: p = 0.72 and Ha: p+0.72 . Calculate the observed z-statistic for the following sample data: Sixty-eight out of ninety test subjects have the characteristic of interest. Round to the nearest thousandth. A. z = 0.751 B. z = 0.756 C. z = 0.453 D. z = - 0.751

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 1GP
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Suppose that the following is to be tested: Ho: p= 0.72 and Ha: p# 0.72. Calculate the observed
z-statistic for the following sample data: Sixty-eight out of ninety test subjects have the characteristic of
interest. Round to the nearest thousandth.
A. z = 0.751
B. z = 0.756
C. z = 0.453
O D. z = - 0.751
Transcribed Image Text:Suppose that the following is to be tested: Ho: p= 0.72 and Ha: p# 0.72. Calculate the observed z-statistic for the following sample data: Sixty-eight out of ninety test subjects have the characteristic of interest. Round to the nearest thousandth. A. z = 0.751 B. z = 0.756 C. z = 0.453 O D. z = - 0.751
Suppose a city official conducts a hypothesis test to test the claim that the majority of voters support a
proposed tax to build sidewalks. Assume that all the conditions for proceeding with a one-sample test on
proportions have been met. The calculated test statistic is approximately 1.40 with an associated p-value
of approximately 0.081. Choose the conclusion that provides the best interpretation for the p-value at a
significance level of a = 0.05.
A. If the null hypothesis is true, then the probability of getting a test statistic that is as extreme or
more extreme than the calculated test statistic of 1.40 is 0.081. This result is surprising and
could not easily happen by chance.
B. The p-value should be considered extreme; therefore the hypothesis test proves that the null
hypothesis is true.
O c. If the null hypothesis is true, then the probability of getting a test statistic that is as extreme or
more extreme than the calculated test statistic of 1.40 is 0.081. This result is not surprising and
could easily happen by chance.
D. None of these.
Transcribed Image Text:Suppose a city official conducts a hypothesis test to test the claim that the majority of voters support a proposed tax to build sidewalks. Assume that all the conditions for proceeding with a one-sample test on proportions have been met. The calculated test statistic is approximately 1.40 with an associated p-value of approximately 0.081. Choose the conclusion that provides the best interpretation for the p-value at a significance level of a = 0.05. A. If the null hypothesis is true, then the probability of getting a test statistic that is as extreme or more extreme than the calculated test statistic of 1.40 is 0.081. This result is surprising and could not easily happen by chance. B. The p-value should be considered extreme; therefore the hypothesis test proves that the null hypothesis is true. O c. If the null hypothesis is true, then the probability of getting a test statistic that is as extreme or more extreme than the calculated test statistic of 1.40 is 0.081. This result is not surprising and could easily happen by chance. D. None of these.
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