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Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed that the mean of this population is 6.25 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 16 college students and record the number of hours each slept the night before finals. Follow the steps below to construct a 95% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Take Sample Sample size: 0 Point estimate: 0 Number of students Sample standard deviation: □ 16 Sample mean 6.615 Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 95% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Standard error: Sample standard deviation Margin of error: 1.662 X S Critical values 0.005=2.947

Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed that the mean of this population is 6.25 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 16 college students and record the number of hours each slept the night before finals. Follow the steps below to construct a 95% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Take Sample Sample size: 0 Point estimate: 0 Number of students Sample standard deviation: □ 16 Sample mean 6.615 Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 95% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Standard error: Sample standard deviation Margin of error: 1.662 X S Critical values 0.005=2.947

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.7: Probability
Problem 58E: What is meant by the sample space of an experiment?
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Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed that the mean of this population is 6.25 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 16 college students and record the number of hours each slept the night before finals. Follow the steps below to construct a 95% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Take Sample Sample size: 0 Point estimate: 0 Sample standard deviation: 0 Critical value: 0 Number of students Compute 16 Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 95% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Sample mean 6.615 Standard error: Margin of error: Sample standard deviation 95% confidence interval: 1.662 Critical values 10.005=2.947 0.010 2.602 10.025 2.131 10.050=1.753 10.100 1.341
Transcribed Image Text:Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed that the mean of this population is 6.25 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 16 college students and record the number of hours each slept the night before finals. Follow the steps below to construct a 95% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Take Sample Sample size: 0 Point estimate: 0 Sample standard deviation: 0 Critical value: 0 Number of students Compute 16 Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 95% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Sample mean 6.615 Standard error: Margin of error: Sample standard deviation 95% confidence interval: 1.662 Critical values 10.005=2.947 0.010 2.602 10.025 2.131 10.050=1.753 10.100 1.341
(b) (c) Based on your sample, graph the 95% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. • Enter the values for the lower and upper limits on the graph to show your confidence interval. • For the point (), enter the claim 6.25 from the report. 0.000 0.000 2.000 95% confidence interval: 4.000 5.000 6.000 8.000 Does the 95% confidence interval you constructed contradict the claim made in the report? Choose the best answer from the choices below. 10.000 10.000 3 O No, the confidence interval does not contradict the claim. The mean of 6.25 hours from the report is inside the 95% confidence interval. No, the confidence interval does not contradict the claim. The mean of 6.25 hours from the report is outside the 95% confidence interval. Yes, the confidence interval contradicts the claim. The mean of 6.25 hours from the report is inside the 95% confidence interval. Yes, the confidence interval contradicts the claim. The mean of 6.25 hours from the report is outside the 95% confidence interval. X
Transcribed Image Text:(b) (c) Based on your sample, graph the 95% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. • Enter the values for the lower and upper limits on the graph to show your confidence interval. • For the point (), enter the claim 6.25 from the report. 0.000 0.000 2.000 95% confidence interval: 4.000 5.000 6.000 8.000 Does the 95% confidence interval you constructed contradict the claim made in the report? Choose the best answer from the choices below. 10.000 10.000 3 O No, the confidence interval does not contradict the claim. The mean of 6.25 hours from the report is inside the 95% confidence interval. No, the confidence interval does not contradict the claim. The mean of 6.25 hours from the report is outside the 95% confidence interval. Yes, the confidence interval contradicts the claim. The mean of 6.25 hours from the report is inside the 95% confidence interval. Yes, the confidence interval contradicts the claim. The mean of 6.25 hours from the report is outside the 95% confidence interval. X
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