Suppose the pump of Fig. P14-23 is operating at efficient condition. The pipe diameter after the pump is "X" cm and pipe diameter before the pump is "Y" diameter. The friction losses along the pipe are negligible (no need to use Darcy Equation). But there are minor losses in the system. They are as follows; the sharp inlet is 0.50 m of water, each valve has a loss of 2.4 m of water, and each of the three elbows has a loss of 0.90 m of water. The contraction at the exit reduces the diameter by a factor of 0.60 (60% of the pipe diameter(after the pump)), and the loss of the contraction is 0.15 m of water. The volume flow rate is "K" Lpm. Density= 990kg/m³. dynamic viscosity=1.002 x10³ kg/m-s. Z1-Z2="L". The kinetic energy correction factor is 1. Determine (a) Required Head, (b) Required pump power (water Hp), (c) Reynolds number at the exit.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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2. Suppose the pump of Fig. P14–23 is operating at efficient condition. The pipe diameter after the pump is
"X" cm and pipe diameter before the pump is "Y" diameter. The friction losses along the pipe are negligible
(no need to use Darcy Equation). But there are minor losses in the system. They are as follows; the sharp
inlet is 0.50 m of water, each valve has a loss of 2.4 m of water, and each of the three elbows has a loss of
0.90 m of water. The contraction at the exit reduces the diameter by a factor of 0.60 (60% of the pipe
diameter(after the pump)), and the loss of the contraction is 0.15 m of water. The volume flow rate is "K"
Lpm. Density= 990kg/m³. dynamic viscosity=1.002 x10³ kg/m-s. Z1-Z2="L". The kinetic energy correction
factor is 1. Determine (a) Required Head, (b) Required pump power (water Hp), (c) Reynolds number at
the exit.
V = 0
Reservoir
Pump
3/4
V2
2
Given for Problem 2
SN
X
Y
K
1
1.51
2.1
90
3.1
Transcribed Image Text:2. Suppose the pump of Fig. P14–23 is operating at efficient condition. The pipe diameter after the pump is "X" cm and pipe diameter before the pump is "Y" diameter. The friction losses along the pipe are negligible (no need to use Darcy Equation). But there are minor losses in the system. They are as follows; the sharp inlet is 0.50 m of water, each valve has a loss of 2.4 m of water, and each of the three elbows has a loss of 0.90 m of water. The contraction at the exit reduces the diameter by a factor of 0.60 (60% of the pipe diameter(after the pump)), and the loss of the contraction is 0.15 m of water. The volume flow rate is "K" Lpm. Density= 990kg/m³. dynamic viscosity=1.002 x10³ kg/m-s. Z1-Z2="L". The kinetic energy correction factor is 1. Determine (a) Required Head, (b) Required pump power (water Hp), (c) Reynolds number at the exit. V = 0 Reservoir Pump 3/4 V2 2 Given for Problem 2 SN X Y K 1 1.51 2.1 90 3.1
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