A fish swimming in a horizontal plane has velocity i = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is i = (12.0 î − 3.60 ĵ) m. After the fish swims with constant acceleration for 17.0 s, its velocity is = (19.0 î − 6.00 ĵ) m/s. A fish swimming in a horizontal plane has velocity v. = (4.00 Î + 1.00 î) m/s at a point in the ocean where the position relative to a certain rock is ř. = (12.0 î - 3.60 j) m. After the fish swims with constant acceleration for 17.0 s, its velocity is v = (19.0 î - 6.00 î)m/s.(a) What are the components of the acceleration of the fish?m/s2m/s2a, =a, =(b) What is the direction of its acceleration with respect to unit vector î?O counterclockwise from the +X-axis(c) If the fish maintains constant acceleration, where is it at t = 30.0 s?y =In what direction is it moving?counterclockwise from the +x-axis

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Description: A fish swimming in a horizontal plane has velocity i = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is i = (12.0 î − 3.60 ĵ) m. After the fish swims with constant acceleration for 17.0 s, its velocity is

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swimming in a horizontal plane has velocity v- (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is r - (12.0 i - 3.60 j) m. After the fish swims with constant acceleration for 17.0 s, its velocity is v - (19.0 i - 6.00 j) (a) What are the components of the acceleration of the fish? m/s m/s? (b) What is the direction of its acceleration with respect to unit vector i? counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t- 30.0 s? m In what direction is it moving? counterclockwise from the +x-axis

swimming in a horizontal plane has velocity v- (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is r - (12.0 i - 3.60 j) m. After the fish swims with constant acceleration for 17.0 s, its velocity is v - (19.0 i - 6.00 j) (a) What are the components of the acceleration of the fish? m/s m/s? (b) What is the direction of its acceleration with respect to unit vector i? counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t- 30.0 s? m In what direction is it moving? counterclockwise from the +x-axis

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 28P: In a classic clip on Americas Funniest Home Videos, a sleeping cat rolls gently off the top of a...

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A fish swimming in a horizontal plane has velocity i = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is i = (16.0 î − 3.20 ĵ) m. After the fish swims with constant acceleration for 15.0 s, its velocity is = (21.0 î − 6.00 ĵ) m/s. (a) What are the components of the acceleration of the fish? ax = m/s2 ay = m/s2 (b) What is the direction of its acceleration with respect to unit vector î? ° counterclockwise from the +x-axis(c) If the fish maintains constant acceleration, where is it at t = 30.0 s? x = m y = m In what direction is it moving? ° counterclockwise from the +x-axis
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