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Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.3MCQ: For an ideal 2-winding transformer, the ampere-turns of the primary winding, N1I1 is equal to the...

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Question

The copper losses of an isolation transformer is 50W at maximum efficiency. If the primary winding resistance is 1 ohms, calculate the load current at maximum efficiency. Draw the phasor diagram on no-load.

Expert Solution

Step 1

Given:

To calculate the load current at maximum efficiency using given values:

$w i n d i n g l o s s e s = 50 W R = 1 o h m$

Step 2

Maximum frequency is given as:

$I^{2} R = 50$

Substituting the values to get the frequency is shown as:

$I^{2} = 50 / 1 I = 7.07 A$

Therefore, the load current is 7.07 A.

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