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Table 2 Trial 1 2 3 4 MV Jov ng equations (1) through (3), to eliminate v, yields w the pendulum to hang freely, and move the angle indicator to zero degrees. ch the pendulum at 90° so it is out of the way, then load the projectile launcher (use long-range). ad the launcher, then set the angle indicator to an angle 1-2° less than that reached in step do this adjustment so as to eliminate the drag on the pendulum caused by the indicator since the um will only move the indicator for the last few degrees. V= тум √2g L(1-1050) thing the angle indicator to a point 1-2° below the previous angle reached by the pendulum each time. Fire the launcher, and record the angle reached by the pendulum in the table. Repeat this several times, Lusing the angle measurements and the pendulum length Rcm, determine the vertical displacement Ah alues for each trial. Record in the table below: 65.89 Mass of the metal ball (mb) Mas of the pendulum (M₂) 247 g Total Mass (M = m + Mp)_212.89 Length of the pendulum (RCM) 30 CM. 5 Vo = M mb being the distance between the center of mass and the axis the rod rotates around, and 9 is Rems e the rod rotates through before stopping. Angle (0) 39° 39.5° 39.5° Mv = (m+M) v' 36⁰° Averager 38.6° √√2g Rem(1-cos 8) Ah RCM (1-cos cos 0) 6.68/ 6.85 6.85 6.68 5.72 Avg: -6.55 Solve for

Table 2 Trial 1 2 3 4 MV Jov ng equations (1) through (3), to eliminate v, yields w the pendulum to hang freely, and move the angle indicator to zero degrees. ch the pendulum at 90° so it is out of the way, then load the projectile launcher (use long-range). ad the launcher, then set the angle indicator to an angle 1-2° less than that reached in step do this adjustment so as to eliminate the drag on the pendulum caused by the indicator since the um will only move the indicator for the last few degrees. V= тум √2g L(1-1050) thing the angle indicator to a point 1-2° below the previous angle reached by the pendulum each time. Fire the launcher, and record the angle reached by the pendulum in the table. Repeat this several times, Lusing the angle measurements and the pendulum length Rcm, determine the vertical displacement Ah alues for each trial. Record in the table below: 65.89 Mass of the metal ball (mb) Mas of the pendulum (M₂) 247 g Total Mass (M = m + Mp)_212.89 Length of the pendulum (RCM) 30 CM. 5 Vo = M mb being the distance between the center of mass and the axis the rod rotates around, and 9 is Rems e the rod rotates through before stopping. Angle (0) 39° 39.5° 39.5° Mv = (m+M) v' 36⁰° Averager 38.6° √√2g Rem(1-cos 8) Ah RCM (1-cos cos 0) 6.68/ 6.85 6.85 6.68 5.72 Avg: -6.55 Solve for

Classical Dynamics of Particles and Systems
Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter9: Dynamics Of A System Of Particles
Section: Chapter Questions
Problem 9.35P
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Table 2 Trial 1 2 3 4 [" 5 m MV ng equations (1) through (3), to eliminate v, yields w the pendulum to hang freely, and move the angle indicator to zero degrees. and the launcher, then set the angle indicator to an angle 1-2° less than that reached in step ch the pendulum at 90° so it is out of the way, then load the projectile launcher (use long-range). do this adjustment so as to eliminate the drag on the pendulum caused by the indicator since the ndalum will only move the indicator for the last few degrees. тум V= 129 L(1-1050) m Solve for vi are the launcher, and record the angle reached by the pendulum in the table. Repeat this several times, thing the angle indicator to a point 1-2° below the previous angle reached by the pendulum each time. Lusing the angle measurements and the pendulum length Rcm, determine the vertical displacement Ah alues for each trial. Record in the table below: as of the metal ball (m) 5.89 Mas of the pendulum (M₂) 247 g Total Mass (M = m₂ + M₂)_212.89 Length of the pendulum (RCM) 30 CM. √√2gRem(1-cos 8) being the distance between the center of mass and the axis the rod rotates around, and 8 is Vo = Rem s e the rod rotates through before stopping. M mb Angle (0) 39° 39.5° 39.5° 39° My = (m+M) v' 36⁰° Averager 38.6° Ah RCM (1-cos cos 0) 6.68/ (4) 6.85 6.85 6.68 5.72 Avg: 6.55 65
Transcribed Image Text:Table 2 Trial 1 2 3 4 [" 5 m MV ng equations (1) through (3), to eliminate v, yields w the pendulum to hang freely, and move the angle indicator to zero degrees. and the launcher, then set the angle indicator to an angle 1-2° less than that reached in step ch the pendulum at 90° so it is out of the way, then load the projectile launcher (use long-range). do this adjustment so as to eliminate the drag on the pendulum caused by the indicator since the ndalum will only move the indicator for the last few degrees. тум V= 129 L(1-1050) m Solve for vi are the launcher, and record the angle reached by the pendulum in the table. Repeat this several times, thing the angle indicator to a point 1-2° below the previous angle reached by the pendulum each time. Lusing the angle measurements and the pendulum length Rcm, determine the vertical displacement Ah alues for each trial. Record in the table below: as of the metal ball (m) 5.89 Mas of the pendulum (M₂) 247 g Total Mass (M = m₂ + M₂)_212.89 Length of the pendulum (RCM) 30 CM. √√2gRem(1-cos 8) being the distance between the center of mass and the axis the rod rotates around, and 8 is Vo = Rem s e the rod rotates through before stopping. M mb Angle (0) 39° 39.5° 39.5° 39° My = (m+M) v' 36⁰° Averager 38.6° Ah RCM (1-cos cos 0) 6.68/ (4) 6.85 6.85 6.68 5.72 Avg: 6.55 65
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