Test the claim that the mean GPA of night students is larger than 2.9 at the 0.05 significance level. The null and alternative hypothesis would be: H0:p≤0.725H0:p≤0.725 H1:p>0.725H1:p>0.725 H0:μ=2.9H0:μ=2.9 H1:μ≠2.9H1:μ≠2.9 H0:p=0.725H0:p=0.725 H1:p≠0.725H1:p≠0.725 H0:p≥0.725H0:p≥0.725 H1:p<0.725H1:p<0.725 H0:μ≤2.9H0:μ≤2.9 H1:μ>2.9H1:μ>2.9 H0:μ≥2.9H0:μ≥2.9 H1:μ<2.9H1:μ<2.9 The test is: left-tailed right-tailed two-tailed Based on a sample of 30 people, the sample mean GPA was 2.95 with a standard deviation of 0.03 The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the mean GPA of night students is larger than 2.9 at the 0.05 significance level. The null and alternative hypothesis would be: H0:p≤0.725H0:p≤0.725 H1:p>0.725H1:p>0.725 H0:μ=2.9H0:μ=2.9 H1:μ≠2.9H1:μ≠2.9 H0:p=0.725H0:p=0.725 H1:p≠0.725H1:p≠0.725 H0:p≥0.725H0:p≥0.725 H1:p<0.725H1:p<0.725 H0:μ≤2.9H0:μ≤2.9 H1:μ>2.9H1:μ>2.9 H0:μ≥2.9H0:μ≥2.9 H1:μ<2.9H1:μ<2.9 The test is: left-tailed right-tailed two-tailed Based on a sample of 30 people, the sample mean GPA was 2.95 with a standard deviation of 0.03 The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Chapter9: Sequences, Probability And Counting Theory
Section9.7: Probability
Problem 1SE: What term is used to express the likelihood of an event occurring? Are there restrictions on its...
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Test the claim that the mean GPA of night students is larger than 2.9 at the 0.05 significance level.
The null and alternative hypothesis would be:
H0:p≤0.725H0:p≤0.725
H1:p>0.725H1:p>0.725
H1:p>0.725H1:p>0.725
H0:μ=2.9H0:μ=2.9
H1:μ≠2.9H1:μ≠2.9
H1:μ≠2.9H1:μ≠2.9
H0:p=0.725H0:p=0.725
H1:p≠0.725H1:p≠0.725
H1:p≠0.725H1:p≠0.725
H0:p≥0.725H0:p≥0.725
H1:p<0.725H1:p<0.725
H1:p<0.725H1:p<0.725
H0:μ≤2.9H0:μ≤2.9
H1:μ>2.9H1:μ>2.9
H1:μ>2.9H1:μ>2.9
H0:μ≥2.9H0:μ≥2.9
H1:μ<2.9H1:μ<2.9
H1:μ<2.9H1:μ<2.9
The test is:
left-tailed
right-tailed
two-tailed
Based on a sample of 30 people, the sample mean GPA was 2.95 with a standard deviation of 0.03
The p-value is: (to 2 decimals)
Based on this we:
- Reject the null hypothesis
- Fail to reject the null hypothesis
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