• Test Tube 1: Calculate the mass in g of product made from 0.50 mL of 0.12 M Na3PO4: Test Tube 2: Calculate the mass in g of product made from mL of 0.12 M Na3PO4:
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- Convert the concentration below to mM and uM:154.5mg of sucrose (Formula Weight: 342.30g/mole) per 300mLMass of Na2CO3=5g Mass of CaCl2=4.98g Mass of filter paper=1.11g Na2CO3 and CaCl2 combined, filtered, and dried overnight. The mass of the solid produced = 2.86g Calculate the theoretical yield of solid expected and the percent yield obtained.1) 11. 3 g BaI2 is dissolved in 145.0 g of H2O. Calculate the percentage concentration (by mass) of BaI2. 2) How many moles of methanol (CH3OH) are in 24.1 mL of 0.818 M CH3OH? 3) How many grams of KNO3 would be needed to prepare a 275 g of a 6.3% KNO3 solution? 4) How many mL of 815 M KI solution are required to react with 50.0 mL of 0.259 M Pb(NO3)2 solution to form lead(II) iodide? Pb(NO3)2 (aq) + 2 KI (aq) à PbI2 (s) + 2 KNO3 (aq)
- What is the molarity of a KCl solution made by diluting 75.0 mL of a 0.200 M solution to a final volume of 100. mL? 0.200 M 0.150 M 0.100 M 0.267 M 6.67 M(a) 4.95 g of NaCl dissolved in 50.6 g of H2O % (b) 1.92 g of LiBr dissolved in 43.0 g of H2O % (c) 24.8 g of KNO3 dissolved in 351 g of H2O % (d) 3.9×10-3 g of NaOH dissolved in 3.3 g of H2O %Dapsone tablets, labelled 50 mg has an average tablet weight of 0.6509 g. 2.0g of powdered tablets reacted (see reaction below) with 26.05 mL of 0.0506N sodium nitrite (NaNO2) solution. Determine the amount of Dapsone as a percentage of the Label Strength (or Label Claim). Report your answer to 1 decimal place. Given: Dapsone molar mass, 248.302 g/mol Dapsone structure Reaction: Sodium nitrite (NaNO2) reacts with hydrochloric acid (HCl) to generate nitrous acid (HNO2). NaNO2 + HCl ® HNO2 + NaCl Nitrous acid (HNO2) then reacts with each amino group on Dapsone, and an indicator indicates the endpoint. R-NH2 (full structure shown above) + HNO2 + HCl ® R-N2Cl + 2H2O
- An engineering student accidently ingests 10 g of paint that contains 5% of lead. How many grams of a salt Na4 (EDTA) he has to ingest to capture the lead as Pb EDTA?a. 10.00 grams of solid potassium hydroxide is added to 250.0 mL of distilled water. Write a chemical equation that describeswhat happens. Calculate the moles of each product.b. 10.00 grams of pure hydrochloric acid is added to 250.0 mL of distilled water. Write a chemical equation that describes whathappens. Calculate the moles of each product. c. The two solutions are mixed together.1. Write a chemical equation that describes what happens.2. Calculate the moles of each product.3. Calculate the molarity of each product.1. Calculate the normality of 0.321 g sodium carbonate (106.0 g/mol) when it is mixed in a 250 mL solution. 2. What is the normality of 0.0521 M H3PO4? 3. A12.5-mL portion of a base solution of an element from group 2A is diluted to 500 mL; the resulting concentration of this solution is determined to be 0.125 M. What is the normality of the original solution. 4. A sample of USP-grade citric acid (H3C6H5O7, three titratable protons) is analyzed by titrating with 0.1087 M NaOH. A 0.2678-g sample requires 38.31 mL of the titrant for titration. A. What is the normality of the titrant? B. What is the stoichiometric relationship between the analyte and the titrant? C. How many moles of the titrant were consumed to react with the analyte? NOTE: please include the given, the unknown, the chemical reaction, the calculation process, and the final answer with the proper number of significant figures.
- I need help finding the therotical yield and the percent yield by finding the limiting reagent based on the data i need the step by step calculations benzaldehyde 1.0 ml 20% NAOH 10 ml 95% ethanol 7.6 mlB. Calculate how many liters of CO2 are produced 1. For 1.25g sodium bicarbonate 2. For 2.8g sodium bicarbonate 3. For 5.0g sodium bicarbonateusing table 1, answer the questiosn below. Mass of Crushed Antacid (g) .500g Concentration of HCl (M) 1.0 M Volume HCl (mL) 5.01ml Concentration of NaOH (M) 1.0M Initial NaOH Volume (mL) 4.10ml Final NaOH Volume (mL) 2.60ml Total Volume of NaOH Used (mL) 1.5ml HCl available for neutralization (g): Moles of NaOH required to reach stoichiometric point (mol): HCl neutralized by antacid (g): HCl neutralized per gram of antacid (g):