The 226Ra nucleus undergoes alpha decay according to the reaction: 226Ra --> 22286Rn + 42He Take the masses to be 226.025 406 u for 226Ra, 222.017 574 u for 222Rn, and 4.002 603 u for 42He. Find the difference in mass between the initial nucleus and the final products, in u. Then use 931 Mev/u to get your answer in energy units Mev.

The 226Ra nucleus undergoes alpha decay according to the reaction: 226Ra --> 22286Rn + 42He Take…

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Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter30: Nuclear Physics

Section: Chapter Questions

Problem 7OQ

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The 226Ra nucleus undergoes alpha decay according to the reaction: ²²⁶Ra --> ²²²₈₆Rn + ⁴₂He Take the masses to be 226.025 406 u for 226Ra, 222.017 574 u for ²²²Rn, and 4.002 603 u for ⁴₂He. Find the difference in mass between the initial nucleus and the final products, in u. Then use 931 Mev/u to get your answer in energy units Mev.

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