The acceleration of a particle moving only on a horizontal xy plane is given by a = 5tî + 6tj, where a is in meters per second-squared and t is in seconds. At t = 0, the position vector 7 = (28.0m)i + (47.0m) locates the paticle, which then has the velocity vector = (4.20m/s)i + (2.10m/s)j. At t = 5.90s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis? (a) Number i (b) Number i î+ i Units Ĵ Units

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
Section: Chapter Questions
Problem 6P: At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of...
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The acceleration of a particle moving only on a horizontal xy plane is given by a = 5tî + 6tj,
where a is in meters per second-squared and t is in seconds. At t = 0, the position vector
(28.0m)i + (47.0m) locates the paticle, which then has the velocity vector
=
✓ = (4.20m/s)i + (2.10m/s)ĵ. At t = 5.90 s, what are (a) its position vector in unit-vector
notation and (b) the angle between its direction of travel and the positive direction of the x axis?
(a) Number i
(b) Number i
î+
i
Units
Ĵ Units
Transcribed Image Text:Current Attempt in Progress The acceleration of a particle moving only on a horizontal xy plane is given by a = 5tî + 6tj, where a is in meters per second-squared and t is in seconds. At t = 0, the position vector (28.0m)i + (47.0m) locates the paticle, which then has the velocity vector = ✓ = (4.20m/s)i + (2.10m/s)ĵ. At t = 5.90 s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis? (a) Number i (b) Number i î+ i Units Ĵ Units
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