The addition of 3.15 g ofBa(OH)2•8H2O to a solution of 1.52 g of NH4SCN in 100 g of water in a calorimeter caused the temperature to fall by 3.1 °C. Assuming the specific heat of the solution and products is 4.20 J/g°C, calculate the approximate amount of heat absorbed by the reaction, which can be represented by the following equation: Ba(OH)2-8H20 + 2NH,SCN Ba(SCN)2 + 2NH3 +10H;O O 136.28 J 1.3628 J O 1362.8 J

Chemistry by OpenStax (2015-05-04)
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Chapter5: Thermochemistry
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Problem 27E: The addition of 3.15 g of Ba(OH)28H2O to a solution of 1.52 g of NH4SCN in loo g of water in a...
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The addition of 3.15 g ofBa(OH)2·8H2O to a solution
of 1.52 g of NHĄSCN in 100 g of water in a
calorimeter caused the temperature to fall by 3.1 °C.
Assuming the specific heat of the solution and
products is 4.2O J/g°C, calculate the approximate
amount of heat absorbed by the reaction, which can
be represented by the following equation:
Ba(OH)2-8H,0 + 2NH,SCN Ba(SCN), + 2NH3 +10H,O
O 136.28 J
1.3628 J
O 1362.8 J
Transcribed Image Text:The addition of 3.15 g ofBa(OH)2·8H2O to a solution of 1.52 g of NHĄSCN in 100 g of water in a calorimeter caused the temperature to fall by 3.1 °C. Assuming the specific heat of the solution and products is 4.2O J/g°C, calculate the approximate amount of heat absorbed by the reaction, which can be represented by the following equation: Ba(OH)2-8H,0 + 2NH,SCN Ba(SCN), + 2NH3 +10H,O O 136.28 J 1.3628 J O 1362.8 J
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