d'udx2 XE10, 1]The adjoint operator of the operator L(u) =with boundary conditions u(1)=2 u(0), and u'(1)=u'(0),isd'vwith boundary conditionsO a.L(v) = -dx22 v(1) = v(0), and v'(0)= v'(1).Ob.= (^)T7with boundary conditionsdx2v(1) = v(0), and v (0)=2 v'(1).d?vwith boundary conditionsL(v)=dx2v(0) = 2 v(1), and v'(0)= v'(1).O d.L(v)= -d'vwith boundary conditionsdx?v(1) = v(0), and v (0) = 2 v'(1).O e.=(^)+ 7d'vwith boundary conditionsdx2v(1) = v(0), and 2v (0)= v'(1).d?vL+(v)=dx2Of.with boundary conditionsv(1) = 2 v(0), and v'(0)= v'(1).

We are given The boundary conditions at x=1 is given as u(1)=2u(0); u'(1)=u'(0)

The adjoint operator of the operator L(u): d'u ;xE[0, 1] %3D dx2 with boundary conditions u(1)=2 u(0), and u'(1)=u'(0), is L(v) = - with boundary conditions d'v dx2 2 v(1) = v(0), and v (0)= v'(1). d'v L (v) = dx2 Ob. with boundary conditions v(1) = v(0), and v (0)=2 v'(1). d?v L(v) = dx2 with boundary conditions v(0)=2 v(1), and v'(0)= v'(1). O d. L(v) = - d'v with boundary conditions dx? v(1) = v(0), and v (0)=2 v'(1). d?v with boundary conditions Oe. = (^)+7 dx2 v(1) = v(0), and 2 v'(0)= v'(1). Of. d?v with boundary conditions dx2 =(^)+7 v(1)= 2 v(0), and v'(0)= v'(1).

The adjoint operator of the operator L(u): d'u ;xE[0, 1] %3D dx2 with boundary conditions u(1)=2 u(0), and u'(1)=u'(0), is L(v) = - with boundary conditions d'v dx2 2 v(1) = v(0), and v (0)= v'(1). d'v L (v) = dx2 Ob. with boundary conditions v(1) = v(0), and v (0)=2 v'(1). d?v L(v) = dx2 with boundary conditions v(0)=2 v(1), and v'(0)= v'(1). O d. L(v) = - d'v with boundary conditions dx? v(1) = v(0), and v (0)=2 v'(1). d?v with boundary conditions Oe. = (^)+7 dx2 v(1) = v(0), and 2 v'(0)= v'(1). Of. d?v with boundary conditions dx2 =(^)+7 v(1)= 2 v(0), and v'(0)= v'(1).

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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