The allowable shear stress in two steel (G = 83 GPa) shafts below is 90 MPa. The design requires that the end D of the shaft CD doesn't rotate more than 4°, and both shafts shall have the same diameter. Determine the required diameter of the shafts.

The allowable shear stress in two steel (G = 83 GPa) shafts below is 90 MPa. The design requires that the end D of the shaft CD doesn't rotate more than 4°, and both shafts shall have the same diameter. Determine the required diameter of the shafts.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter3: Torsion

Section: Chapter Questions

Problem 3.12.4P: The stepped shaft shown in the figure is required to transmit 600 kW of power at 400 rpm. The shaft...

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Concept explainers

Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.

Question

4. The allowable shear stress in two steel (G = 83 GPa) shafts below is 90 MPa. The
design requires that the end D of the shaft CD doesn't rotate more than 4°, and both
shafts shall have the same diameter. Determine the required diameter of the shafts.
40 mm
T = 1000 N - m
D
100 mm
400 mm
600 mm

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