The amount of time adults spend watching television is closely monitored by firms because this helps to determine advertising pricing for commercials. Completeparts (a) through (d)......(a) Do you think the variable "weekly time spent watching television" would be normally distributed? If not, what shape would you expect the variable to have?A. The variable "weekly time spent watching television" is likely symmetric, but not normally distributed.B. The variable "weekly time spent watching television" is likely uniform, not normally distributed.C. The variable "weekly time spent watching television" is likely skewed right, not normally distributed.D. The variable "weekly time spent watching television" is likely normally distributed.E. The variable "weekly time spent watching television" is likely skewed left, not normally distributed.(b) According to a certain survey, adults spend 2.25 hours per day watching television on a weekday. Assume that the standard deviation for "time spent watchingtelevision on a weekday" is 1.93 hours. If a random sample of 40 adults is obtained, describe the sampling distribution of x, the mean amount of time spent watchingtelevision on a weekday.V withand ox0- =%3D(Round to six decimal places as needed.)(c) Determine the probability that a random sample of 40 adults results in a mean time watching television on a weekday of between 2 and 3 hours.The probability is|. (Round to four decimal places as needed.)(d) One consequence of the popularity of the Internet is that it is thought to reduce television watching. Suppose that a random sample of 35 individuals whoconsider themselves to be avid Internet users results in a mean time of 1.81 hours watching television on a weekday. Determine the likelihood of obtaining a samplemean of 1.81 hours or less from a population whose mean is presumed to be 2.25 hours.The likelihood is(Round to four decimal places as needed.)Interpret this probability. Select the correct choice below and fill in the answer box within your choice.(Round to the nearest integer as needed.)O A. If 1000 different random samples of size n = 35 individuals from a population whose mean is assumed to be 2.25 hours is obtained, we would expect asample mean of exactly 1.81 in aboutof the samples.B. If 1000 different random samples of size n = 35 individuals from a population whose mean is assumed to be 2.25 hours is obtained, we would expect asample mean of 1.81 or more in aboutof the samples.O C. If 1000 different random samples of size n = 35 individuals from a population whose mean is assumed to be 2.25 hours is obtained, we would expect asample mean of 1.81 or less in aboutof the samples.Based on the result obtained, do you think avid Internet users watch less television?NoYesO O

Question

The amount of time adults spend watching television is closely monitored by firms because this helps to determine advertising pricing for commercials. Completeparts (a) through (d)......(a) Do you think the variable &#34;weekly time spent watching television&#34; would be normally distributed? If not, what shape would you expect the variable to have?A. The variable &#34;weekly time spent watching television&#34; is likely symmetric, but not normally distributed.B. The variable &#34;weekly time spent watching television&#34; is likely uniform, not normally distributed.C. The variable &#34;weekly time spent watching television&#34; is likely skewed right, not normally distributed.D. The variable &#34;weekly time spent watching television&#34; is likely normally distributed.E. The variable &#34;weekly time spent watching television&#34; is likely skewed left, not normally distributed.(b) According to a certain survey, adults spend 2.25 hours per day watching television on a weekday. Assume that the standard deviation for &#34;time spent watchingtelevision on a weekday&#34; is 1.93 hours. If a random sample of 40 adults is obtained, describe the sampling distribution of x, the mean amount of time spent watchingtelevision on a weekday.V withand ox0- =%3D(Round to six decimal places as needed.)(c) Determine the probability that a random sample of 40 adults results in a mean time watching television on a weekday of between 2 and 3 hours.The probability is|. (Round to four decimal places as needed.)(d) One consequence of the popularity of the Internet is that it is thought to reduce television watching. Suppose that a random sample of 35 individuals whoconsider themselves to be avid Internet users results in a mean time of 1.81 hours watching television on a weekday. Determine the likelihood of obtaining a samplemean of 1.81 hours or less from a population whose mean is presumed to be 2.25 hours.The likelihood is(Round to four decimal places as needed.)Interpret this probability. Select the correct choice below and fill in the answer box within your choice.(Round to the nearest integer as needed.)O A. If 1000 different random samples of size n = 35 individuals from a population whose mean is assumed to be 2.25 hours is obtained, we would expect asample mean of exactly 1.81 in aboutof the samples.B. If 1000 different random samples of size n = 35 individuals from a population whose mean is assumed to be 2.25 hours is obtained, we would expect asample mean of 1.81 or more in aboutof the samples.O C. If 1000 different random samples of size n = 35 individuals from a population whose mean is assumed to be 2.25 hours is obtained, we would expect asample mean of 1.81 or less in aboutof the samples.Based on the result obtained, do you think avid Internet users watch less television?NoYesO O

Accepted Answer

Here AS PER POLICY I HAVE CALCULATED 3 SUBPART PLZ REPOST FOR REMAINING PARTS 
Here given survey is…