The atomic masses of hydrogen-2 (deuterium), helium-4, and lithium-6 are 2.014102 amu, 4.002602 amu, and 6.0151228 amu, respectively. For each isotope, calculate the nuclear binding energy,

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Chapter19: Radioactivity And Nuclear Energy
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Problem 52A
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The atomic masses of hydrogen-2 (deuterium), helium-4, and lithium-6 are 2.014102 amu, 4.002602 amu, and 6.0151228 amu, respectively. For each isotope, calculate the nuclear binding energy,

Expert Solution
Introduction-

Binding energy is the amount of energy required to disassemble the particles from the atom.

Nuclear Binding energy is the minimum amount of energy required to disassemble the nucleus into its constituent parts called the nucleons.

It is calculated by the formula BE= ∆mc2

∆m – change in mass during the reaction.

c- Velocity of light that is 3×108 m/s.

Now we can calculate the change in mass with the help of following formula-

∆m = m (Theoretical) – m (experimental)

Theoretical mass means mass of protons and electrons and neutrons present. Experimental mass means the given value after experimental data.

Explanation-

Given-

Atomic mass of Deuterium 1H2 = 2.014102 amu

Atomic mass of Helium 2He4= 4.002602 amu

Atomic mass of Lithium 3Li6 = 6.0151228 amu

Calculation-

Theoretical mass for Deuterium = mass of 1 neutron+mass of 1electron +mass of a proton

Theoretical mass for Deuterium = (1.008665 amu+0.000548597amu + 1.00727647 amu)

Theoretical mass for Deuterium =2.016490067 amu

∆m of Deuterium= m (Theoretical) – m (experimental)

∆m of Deuterium= 2.016490067 amu - 2.014102 amu

∆m of Deuterium=0.002388067amu

∆m of Deuterium=3.965478199456 ×10-27 g

BE of Deuterium= ∆mc2

BE of Deuterium = 3.9654×10-27 g× (3×108)2

BE of Deuterium = 3.568× 10-12gm2/s2

BE of Deuterium =3.568× 10-12J

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