The average salary of 36 employee was 4650 and the sample standard deviation was 165. Find the 99% confidence interval for the population mean salary. Select one: a. 4650 + 67.05 b. 4650 ± 45.24 O c. 4650 + 55.83 O d. 4650 + 46.48 O e. 4650 + 70.84 O f. 4650 ± 74.91 O g. 4650 + 53.90 O h. 4650 ± 63.97

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