The base composition of the transcribable DNA template is: A = 10% G = 40% C = 30% T= 20% %3D %3D What is the base composition of the transcribed product? A. A = 20%; C = 40% B. G = 30%; C = 20% C. G = 10%; T= 20% %3D D. C = 10%; U = 40% E. Cannot be determined
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Bacterial Genomics
The study of the morphological, physiological, and evolutionary aspects of the bacterial genome is referred to as bacterial genomics. This subdisciplinary field aids in understanding how genes are assembled into genomes. Further, bacterial or microbial genomics has helped researchers in understanding the pathogenicity of bacteria and other microbes.
Transformation Experiment in Bacteria
In the discovery of genetic material, the experiment conducted by Frederick Griffith on Streptococcus pneumonia proved to be a stepping stone.
Plasmids and Vectors
The DNA molecule that exists in a circular shape and is smaller in size which is capable of its replication is called Plasmids. In other words, it is called extra-chromosomal plasmid DNA. Vectors are the molecule which is capable of carrying genetic material which can be transferred into another cell and further carry out replication and expression. Plasmids can act as vectors.
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- When joining two or more DNA fragments, a researcher can adjust the sequence at the junction in a variety of subtle ways, as seen in the following exercises.(a) Draw the structure of each end of a linear DNA fragment produced by an EcoRI restriction digest (include those sequences remaining from the EcoRI recognition sequence).(b) Draw the structure resulting from the reaction of this end sequence with DNA polymerase I and the four deoxynucleoside triphosphates.(c) Draw the sequence produced at the junction that arises if two ends with the structure derived in (b) are ligated (d) Draw the structure produced if the structure derived in (a) is treated with a nuclease that degrades only single-stranded DNA.(e) Draw the sequence of the junction produced if an end with structure (b) is ligated to an end with structure (d).(f) Draw the structure of the end of a linear DNA fragment that was produced by a PvuII restriction digest (include those sequences remaining from the PvuII recognition…the most efficient general strategy for whole genome sequencing is ? (a) double the coding sequence after sequencing the proteins (b) shotgun sequence and assemble based on overlaps (c) identify mutations that affect glycolysis (d) obtain recombinant DNA clone maps before starting the sequencing (e) obtain comprehensive SNP maps before determining the order of DNA cloneYou are performing a PCR reaction but unbeknownst to you, there is a significant pool of dUTP in the nucleotide mix (along with dCTP, dTTP, dATP, and dGTP). How might this affect your PCR product? a. If the PCR product was ligated into a plasmid and put into a cell, a totally different mRNA would be made from the insert compared to an insert made with T's. b. If the pool of dTTP ran out before the pool of dUTP, DNA replication could no longer occur. c. During the reaction, uracils incorporated into the product would cause the PCR product to degrade as it is being made. d. Uracil would be incorporated into the product and would lessen the affinity of any DNA binding proteins that might bind to the product in subsequent experiments. e. Nothing would happen since polymerases can't use dUTP to make DNA.
- You obtained the sequence of the frog gene X you amplified in Question #16 through a process called automated sequencing. In automated sequencing, you are given a printout of the sense strand of your DNA. T he printout is shown below. ' The first thing you need to do is use the correct reading frame. Having done this, the next thing to do is to write out the mRNA sequence using this sense strand reading frame. The last thing to do is to translate the sequence. The reading frame DNA sequence is: The mRNA sequence is: The polypeptide sequence is: A disease in frogs which causes their tongue to fall out of their mouths is killing the frog population in LA County. You obtain a dead frog and isolate its gene Xf. When you sequence this mutated gene, you find that the last ‘G’ at the end of the first line of this sequence has been deleted (i.e. the G at position 86). In order to determine how this mutation changes the resulting polypeptide, write the mutated polypeptide sequence in the…Certain restriction endonucleases produce cohesive (sticky) ends. This means that they: a. stick tightly to the ends of the DNA they have cut. b. cut both DNA strands at the same base pair. c. make a staggered double-strand cut, leaving ends with a few nucleotides of single-stranded DNA protruding. d. cut in regions of high GC content, leaving ends that can form more hydrogen bonds than ends of high AT content. e. cut in regions of high AT content, leaving ends that can form more hydrogen bonds than ends of high GC content.Complete the table below 6. Below are several DNA sequences that are mutated compared with the wild-type sequence: 3’-T A C T G A C T GA C G A T C-5’. Envision that each is a section of a DNA molecule that has separated in preparation for transcription, so you are only seeing the template strand. Construct the complementary DNA sequences (indicating 5’ and 3’ ends) for each mutated DNA sequence, then transcribe (indicating 5’ and 3’ ends) the template strands, and translate the mRNA molecules using the genetic code, recording the resulting amino acid sequence (indicating the N and C termini). What type of mutation is each?6.a. Mutated DNA Template Strand #1: 3’-T A C T G T C T G A C G A T C-5’Complementary DNA sequence:mRNA sequence transcribed from template:Amino acid sequence of peptide:Type of mutation: 6.b. Mutated DNA Template Strand #2: 3’-T A C G G A C T G A C G A T C-5’Complementary DNA sequence:mRNA sequence transcribed from template:Amino acid sequence of peptide:Type of…
- Put the following tasks in the order they would occur during a DNA cloning experiment. a. using DNA ligase to seal DNA fragments into vectors b. using a probe to identify a clone in the library c. sequencing the DNA of the clone d. making a DNA library of clones e. cutting genomic DNA with restriction enzymesRestriction enzymes cut double-stranded DNA _____. a. at noncoding areas between genes b. between bacterial and viral DNAs c. at specific base sequences d. between purines and pyrimidines e. between promoter and operator DNA sequencesYou are trying to clone a gene, You have successfully isolated it from the genomic DNA of an organism using the Hindill restriction enzyme. You then take a plasmid with a single EcoRI restriction site and cleave it with EcoRI. You combine these two fragments and treat them with DNA ligase. Answer the two questions below. a. Does the cloning reaction succeed as described? If so, what is the product obtained? b. Explain your answer above,
- a. If you forgot to add dNTPs to a sequencing reaction, what would be the result? Only very long fragments would be synthesized Only very short fragments would be synthesized The fragments would not be labelled DNA polymerase would be inactivated Sequencing would proceed normally b. Please also answer the imageYou obtained the sequence of the frog gene X you amplified in Question #16 through a process called automated sequencing. In automated sequencing, you are given a printout of the sense strand of your DNA. The first thing you need to do is use the correct reading frame. Having done this, the next thing to do is to write out the mRNA sequence using this sense strand reading frame. The last thing to do is to translate the sequence. a.The reading frame DNA sequence is: b.The mRNA sequence is: c.The polypeptide sequence is: A disease in frogs which causes their tongue to fall out of their mouths is killing the frog population in LA County. You obtain a dead frog and isolate its gene Xf. When you sequence this mutated gene, you find that the last ‘G’ at the end of the first line of this sequence has been deleted (i.e. the G at position 86). In order to determine how this mutation changes the resulting polypeptide, write the mutated polypeptide sequence in the space below. What kind of…Which of the following subunits of DNA polymerase has proofreading ability? a. α b. β2 c. θ d. None of the above