The body in the figure is pivoted at O. Three forces act on it in the directions shown on the figure. FA = 11 N at point A, 8.0 m from O. FB = 15 N at point B, 4.0 m from 0. Fc = 20 N at pointC, 3.0 m from O. What is the net torque about O? (Include the sign of the value in your answer. Assume counterclockwise rotation to be positive.)N. mFc135%160°90°B

The given force FA=11N, FB=15N, FC=20NAnd from figure OA=8m, OB=4m, OC=3m

The body in the figure is pivoted at O. Three forces act on it in the directions shown on the figure. FA = 11 N at point A, 8.0 m from O. FR = 15 N at point B, 4.0 m from O. FC = 20 N at point C, 3.0 m from O. What is the net torque about O? (Include the sign of the value in your answer. Assume counterclockwise rotation to be positive.) N.m 135° A 160° 90

The body in the figure is pivoted at O. Three forces act on it in the directions shown on the figure. FA = 11 N at point A, 8.0 m from O. FR = 15 N at point B, 4.0 m from O. FC = 20 N at point C, 3.0 m from O. What is the net torque about O? (Include the sign of the value in your answer. Assume counterclockwise rotation to be positive.) N.m 135° A 160° 90

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter10: Rotational Motion

Section: Chapter Questions

Problem 5OQ: Assume a single 300-N force is exerted on a bicycle frame as shown in Figure OQ10.5. Consider the...

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