The cell potential of the reaction:PbSO4(aq) + Cr(s) ⇒ Pb(s) + Cr²+ (aq) + SO4²-(aq)is +0.55 V. This fact indicates thatThe reducing ability of Cr is 0.55 greater than thatof Pb.Cr2+is a stronger oxidizing agent than PbSO4.Cr is a weaker reducing agent than Pb.Cr²+ is a weaker oxidizing agent than Pb²+.

Reducing agent is the substance which reduces others and oxidize itself. Oxidizing agent is the…

Answered: The cell potential of the reaction:…

The cell potential of the reaction: PbSO4(aq) + Cr(s) ⇒ Pb(s) + Cr²+ (aq) + SO4²- (aq) is +0.55 V. This fact indicates that The reducing ability of Cr is 0.55 greater than that of Pb. 2+.

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter17: Electrochemistry And Its Applications

Section: Chapter Questions

Problem 50QRT

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Concept explainers

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

The cell potential of the reaction:
PbSO4(aq) + Cr(s) ⇒ Pb(s) + Cr²+ (aq) + SO4²-
(aq)
is +0.55 V. This fact indicates that
The reducing ability of Cr is 0.55 greater than that
of Pb.
Cr2+
is a stronger oxidizing agent than PbSO4.
Cr is a weaker reducing agent than Pb.
Cr²+ is a weaker oxidizing agent than Pb²+.

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Calculate the cell potential of a cell operating with the following reaction at 25C, in which [Cr2O32] = 0.020 M, [I] = 0.015 M, [Cr3+] = 0.40 M, and [H+] = 0.60 M. Cr2O72(aq)+6I(aq)+14H+(aq)2Cr3+(aq)+3I2(s)+7H2O(l)
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