The challenge here is to read n lines of input until you reach EOF, then number and print all n lines of content. Hint: Java's Scanner.hasNext() method is helptul for this problem.
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- NEED HELP PLEASE! Write a Java program to read a text file (command line input for file name), process the text file and perform the following. Print the total number of words in the file. Print the total number of different words (case sensitive, meaning “We” and “we” are two different words) in the file. Print all words in ascending order (based on the ASCII code) without duplication. Write a pattern match method to find the location(s) of a specific word (a character string up to twelve characters, e.g. system). This method should return all line number(s) and location(s) of the word(s) found in the file. Print all line(s) with line number(s) of the file where the word is funds by invoking the method of 4). Under each output line indicate the location(s) of the first character of the matched word (refer to the output example below). Empty lines are lines, they also have their own unique line numbers. Repeat the pattern match (4 and 5 above) until user types in EINPUT. A word is…A .The following JavaScript command adds a method to a built-in class that can be called on any object instance of that class.Array.prototype.scramble = function() { this.sort(function() { return 0.5 – Math.random(); });} Select one: True False B. Suppose you have written a JavaScript for loop, and one of the statements that will execute with each iteration of the loop includes an anonymous function that uses the for loop’s counter variable, i. Which statement about this loop is true? a.The anonymous function will execute when it is called by the program, using the value ofiat the time it was encountered in the loop. b. The anonymous function will throw an error if it is called by the program after theforloop has finished iterating. c. The anonymous function will execute when it is called by the program, using the value ofiafter the final iteration of the loop. d.The forloop signals the JavaScript interpreter to copy the body of the anonymous function but not its…JAVA PPROGRAM I have provided the failed test cases and the inputs as a screenshot. Please Modify this program with further modifications as listed below: The program must pass the test case when uploaded to Hypergrade. ALSO, take out the following in the program: System.out.println("Program terminated."); because the test case does not need it. And change this in the program: Please enter the file name or type QUIT to exit:\n so it reperats once for every test case. import java.io.*;import java.util.ArrayList;import java.util.Scanner;public class SymmetricalNameMatcher { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String fileName; do { // Prompt the user to enter a file name or 'QUIT' to exit. System.out.print("Please enter the file name or type QUIT to exit:\n"); fileName = scanner.nextLine(); if (fileName.equalsIgnoreCase("QUIT")) { // If the user types…
- Need help writing this java code, it has three objectives: to process strings to compare, search, sort, and verify location of specific pattern to output result via interface Description Write a Java program to read a text file (command line input for file name), process the text file and perform the following. Print the total number of words in the file. (When using java_test.txt, I calculate the number of words, including number, as 254.) Print the total number of different words (case sensitive, meaning “We” and “we” are two different words) in the file. (When using java_test.txt, I calculate the number of different words, including number, as 168.) Print all words in ascending order (based on the ASCII code) without duplication. Write a pattern match method to find the location(s) of a specific word. This method should return all line number(s) and location(s) of the word(s) found in the file. Print all line(s) with line number(s) where the word is found by invoking the method…I need a simple Java program example that secures sensitive information. The secure example should use char arrays or the securestring class as is talked about in the below paragraph. It would be nice to have two examples ie an unsecure example and then a secure example. Please and thank you Sensitive data can be exposed when it is left in memory. In Java, objects are stored in the heap memory. If sensitive data like passwords, credit card numbers, etc., are stored in String objects, they will remain in the memory until garbage is collected, which can be an indefinite amount of time. During this time, a memory dump could expose this sensitive data. To mitigate this, one can use char arrays or the SecureString class, which allows for the data to be cleared from memory immediately after use.Java Proram ASAP Please improve and adjust the program which is down below with the futher moddifications because it does not pass the test cases in Hypergrade. Please remove /n from the program and for test case 4 after this line: Please re-enter the file name or type QUIT to exit:\n quitENTER there needs to be nothing. import java.io.*;import java.util.Scanner;public class ConvertText { public static void main(String[] args) throws Exception { Scanner sc = new Scanner(System.in); System.out.println("Please enter the file name or type QUIT to exit:"); while (true) { String input = sc.next(); if (input.compareTo("QUIT") == 0) { break; } else { String filePath = new File("").getAbsolutePath(); filePath = filePath.concat("/"); filePath = filePath.concat(input); File file = new File(filePath); if (file.exists() && !file.isDirectory()) {…
- Java Proram ASAP Please improve and adjust the program which is down below with the futher moddifications because it does not pass the test cases in Hypergrade. Please remove /n from the program and for test case 4 after this line: Please re-enter the file name or type QUIT to exit:\n quitENTER there needs to be nothing. import java.io.*;import java.util.Scanner;public class ConvertText { public static void main(String[] args) throws Exception { Scanner sc = new Scanner(System.in); System.out.println("Please enter the file name or type QUIT to exit:"); while (true) { String input = sc.next(); if (input.compareTo("QUIT") == 0) { break; } else { // Get the absolute path of the current directory String filePath = new File("").getAbsolutePath(); filePath = filePath.concat("/"); filePath = filePath.concat(input); File file = new File(filePath);…instructions are in photo and links in photos has code which I have pasted to make it easy to copy. Below is my professor code for Sudoku #2, please make a different version of this code with the same functions as i can not use my teacher's code Sudoku #2 code import java.util.*;import java.io.*; public class MySudokuBoard {public final int SIZE = 9;protected char[][] myBoard;public MySudokuBoard(String theFile) {myBoard = new char[SIZE][SIZE];try {Scanner file = new Scanner(new File(theFile));for(int row = 0; row < SIZE; row++) {String theLine = file.nextLine();for(int col = 0; col < theLine.length(); col++) {myBoard[row][col] = theLine.charAt(col);}}} catch(Exception e) {System.out.println("Something went wrong :(");e.printStackTrace();}}public boolean isSolved() {if(!isValid())return false;Map<Character,Integer> map = new HashMap<>();for(char[] row : myBoard) {for(char cell : row) {if(map.containsKey(cell))map.put(cell, map.get(cell) + 1);elsemap.put(cell, 1);}}//…<<Write in Java>> - Challenge 7 File encryption is the science of writing the contents of a file in a secret code. Your encryption program should work like a filter, reading the contents of one file, modifying the data into a code, and then writing the coded contents out to a second file. The second file will be a version of the first file, but written in a secret code. Although there are complex encryption techniques, you should come up with a simple one of your own. For example, you could read the first file one character at a time, and add 10 to the character code of each character before it is written to the second file. - Challenge 8 Write a program that decrypts the file produced by the program in Programming Challenge 7. The decryption program should read the contents of the coded file, restore the data to its original state, and write it to another file
- JAVA PPROGRAM ASAP Please Modify this program ASAP BECAUSE IT IS MY MIDTERM so it passes all the test cases. It does not pass the test cases when I upload it to Hypergrade. Because RIGHT NOW IT PASSES 1 OUT OF 7 TEST CASES. And dont forget to take out and change the following in the program: System.out.println("Program terminated."); because the test case does not need it And change this in the program: Please enter the file name or type QUIT to exit:\n so it reperats once for every test case because it repeats twice in every case as shown in the screenshot. I only need it once. I have provided the failed the test cases and the inputs as a screenshot. The program must pass the test case when uploaded to Hypergrade. import java.io.*;import java.util.ArrayList;import java.util.Scanner;public class SymmetricalNameMatcher { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String fileName; do { // Prompt the user…In java, without Arrays and using only String methods ( don't use String builder) // Question 17: In MS-DOS, a file name consists of up // to 8 characters (excluding '.', ':', backslask, '?', // and '*'), followed by an optional dot ('.' character) // and extension. The extension may contain zero to three // characters. For example, 1STFILE.TXT is a valid filename. // Filenames are case-blind. // // Write and test a method that takes // in a String, validates it as a valid MS-DOS file // name, appends the extensions ".TXT" if no extension // is given (that is, no '.' appears in FILENAME), converts // the name to uppercase, and returns the resulting string // to the calling method // If fileName ends with a dot, remove that dot and do not // append the default extension. If the name is invalid, // validFileName should return null. public String validFileName(String n) { }REUPLOAD: I need to fill the program to its designated output I have inserted sample runs and the template of codes that will be used(?) Thank you! I TYPED DOWN THE CODE W/ THE PICTURE ATTACHED: import java. util. Formatter;import java. util. Scanner;public class Chupapi {private static Formatter output;public static void main (String[] args) throws Exception {output = new Formatter("output.txt");Scanner in = new Scanner(System.in);} // This method has one parameter and will return the string with all uppercase characters.public static String toUpperCase(String str) {// This method has one parameter and will return the number of vowels in the string.public static int countVowels(String str) {int numvowels = 0;return numvowels;}// This method has one parameter and Witt return true if the string is o pot indrome,// fotse if the string is not o potindrome.public static boolean isPalindrome(String str){boolean isReversible;return isReversible;}//This method hos three porometers and will…