The code I am using will not return the correct type. For example the expected answer is [1] and my code returns 1. I am at a loss for how to fix this. The code is below. def give_change(amount, coins): if amount == 0: return 0 change = [0] change2 = [] nc = 0 done = [False] * (amount+1) done [0] = True while change: nc+= 1 for v in change: for coin in coins: if coin == amount: return nc elif coin > amount: continue elif not done[coin]: done[coin]=True change2.append(coin) change, change2 = change2, [] return coins amount = (1) coins = [1,3] print(give_change(amount,coins))
The code I am using will not return the correct type. For example the expected answer is [1] and my code returns 1. I am at a loss for how to fix this. The code is below. def give_change(amount, coins): if amount == 0: return 0 change = [0] change2 = [] nc = 0 done = [False] * (amount+1) done [0] = True while change: nc+= 1 for v in change: for coin in coins: if coin == amount: return nc elif coin > amount: continue elif not done[coin]: done[coin]=True change2.append(coin) change, change2 = change2, [] return coins amount = (1) coins = [1,3] print(give_change(amount,coins))
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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The code I am using will not return the correct type. For example the expected answer is [1] and my code returns 1.
I am at a loss for how to fix this. The code is below.
def give_change(amount, coins):
if amount == 0:
return 0
change = [0]
change2 = []
nc = 0
done = [False] * (amount+1)
done [0] = True
while change:
nc+= 1
for v in change:
for coin in coins:
if coin == amount:
return nc
elif coin > amount:
continue
elif not done[coin]:
done[coin]=True
change2.append(coin)
change, change2 = change2, []
return coins
amount = (1)
coins = [1,3]
print(give_change(amount,coins))
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