The current and voltage at the terminals of the capacitor in the circuit in (Figure 1) are i(t) = 3.5e 2500 mA, v(t) = (40-26e-2500t) V, where t is in seconds. Figure Is R t≥ 0+ t≥ 0 't = 0 1 < 1 of 1 > + C vc ✓ Correct Part D Specify the numerical value of C. Express your answer to three significant figures and include the appropriate units. View Available Hint(s) Hint 1. How to approach the problem Write the equations for the capacitor current and voltage in terms of Is, Vo, R, C, and t, using the RC step-response method. Compare them with the equations given in the problem statement. u 1 Ω % O 2 X ? Submit Previous Answers Request Answer wwwww c= 46.154 uF You have already submitted this answer. Enter a new answer. No credit lost. Try again.

The current and voltage at the terminals of the capacitor in the circuit in (Figure 1) are i(t) = 3.5e 2500 mA, v(t) = (40-26e-2500t) V, where t is in seconds. Figure Is R t≥ 0+ t≥ 0 't = 0 1 < 1 of 1 > + C vc ✓ Correct Part D Specify the numerical value of C. Express your answer to three significant figures and include the appropriate units. View Available Hint(s) Hint 1. How to approach the problem Write the equations for the capacitor current and voltage in terms of Is, Vo, R, C, and t, using the RC step-response method. Compare them with the equations given in the problem statement. u 1 Ω % O 2 X ? Submit Previous Answers Request Answer wwwww c= 46.154 uF You have already submitted this answer. Enter a new answer. No credit lost. Try again.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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The switch has been in position a for a long time when it is moved to position b at time t = 0. The values for the circuit are as follows:Ia = 0.250A, Ra = 44.0Ω, Rb = 37.0Ω, Rc = 24.0Ω, Rd = 20.0Ω, Re = 30.0Ω, Ve = 45.0V, C = 40.0μF. Recall that for a capacitor, i=C·dv/dt. (Hint: source transformations might help as well.) When the switch has been in position a for a long time, solve for the voltage across Rb, and the voltage across the capacitor. Solve for the voltage across the capacitor immediately after the switch is moved to position b at t = 0, and explain why. After the switch is moved to position b, solve for the time constant of the circuit. Solve for the voltage across the capacitor v(t) as a function of time, when t ≥ 0.
A resistor (R = 1 Ω), inductor (L = 0.1 H) and capacitor (C = 0.1 F) are connected in series, and the current I(t) through the circuit is measured as shown in the image below Assuming that the capacitor is uncharged at t = 0, and that the circuit is electrically small (such that propagation times between components can be neglected), find (or approximate where necessary) for times t = [0 : 0.1 : 0.4] (i.e. do not calculate at t = 0.5) : (shown in the image below)
The current in a 20 mH inductor is known to be i=40 mA,t≤0; i=A1e−10,000t+A2e−40.000tA,t≥0. The voltage across the inductor (passive sign convention) is 28 V at t=0. 1. Find the expression for the voltage across the inductor for t>0. 2. Find the time, greater than zero, when the power at the terminals of the inductor is zero.
A 20μF capacitor is subjected to a voltage pulse having a duration of 1 s. The pulse is described by the following equations: vc(t)={30t2 V,0≤t≤0.5 s;30(t−1)2 V,0.5 s≤t≤1 s;0elsewhere. Sketch the current pulse that exists in the capacitor during the 1 s interval.
Can you please help with this question? The triangular voltage pulse shown below is applied to a 200 mF capacitor. a) Write the expressions thatdescribe vc(t) in the five time intervals t < 0, 0 ≤ t ≤ 2 , 2 ≤ t ≤ 6, 6 ≤ t ≤ 8, and t > 8. b) Derive theexpressions for the capacitor current, power, and energy for the time intervals in part (a).
COURSE: Electrical EngineeringSUBJECT: Electrical ApparatusINSTRUCTIONS:• Write the GIVEN with their respective symbols and units.• Do not skip the SOLUTIONS, do it step-by-step with their respective symbols and units• Round up to 3 three decimal places the FINAL ANSWERS and BOX it. PROBLEM:A capacitor in series with a 66 Ω resistor is connected to a 120 V, 60 Hz source. If the impedance of the circuit is 116 Ω, determine the size of the capacitor.
An electrical circuit has a very small resistance so it can be despised. The capacitor on the left was charged up to the voltage of Vo=10 volts and then, at time t=0, the switch S was closed. The capacity of the capacitors are C=60 µF, and the coil inductance is L=0.04 HI) Find the voltage on the left capacitor, at the instant V1=0.001 s.II) Find the voltage in the right capacitor, at the instant t=002 s.
All capacitors were initially discharged. at t = 0, S1 is placed at position 1 and S2 is closed. During this phase, it has been determined that Eth and Rth seen by the equivalent capacitor are, respectively, 16 V and 11.0 kΩ. The equivalent capacitor is 1.50 µF. Calculate the time constant for this phase. Enter your answer in ms rounded to 2 decimal places. At t = 15 ms, S1 is placed at position 2 and S2 is kept closed. At t = 25 ms, S1 is kept at position 2 and S2 is opened. Data: R1 = 5 kΩ, R2 = 4 kΩ, R4 = 3 kΩ, R5 = 18 kΩ, R6 = 12.5 kΩ;
A series circuit has a capacitor of 1.5625x10^(-8)F a resistor of 2x10^4 ohms, and an inductor of 1H. If the initial charge on the capacitor is zero,. if a 12-volt battery is connected to the circuit and the circuit is closed at t=0, determine the charge on the capacitor at any time t
The potential difference between the terminals of the capacitor at the initial (t = 0) moment in the RC circuit given in Figure 3.is zero (VC (0) = 0V). At t = 0 the switch is closed. Element values: E = 10V, R = 100kΩ, C = 7µF.VC (t) = E (1 - e− t / RC) (a) After three seconds, the capacitor voltage becomes 5V? (VC (t) = 5V) (b) After 2 seconds, how many Volts will the capacitor voltage be? (VC (2) =?)
The initial value of the voltage v in the circuit is zero,and the initial value of the capacitor current, ic(0+), is 45 mA. Theexpression for the capacitor current is known to beic(t)=A1e−200t+A2e−800t, t≥0+,when R is 250 Ω. Find1. the values of α, ω0, L, C, A1, and A2(Hint:diC(0+)dt=−diL(0+)dt−diR(0+)dt=−v(0)L−1RiC(0+)C)1. the expression for v(t), t≥0,2. the expression for iR(t)≥0,3. the expression for iL(t)≥0
Calculate the equivalent capacitance in the circuit. Enter your answer in µF rounded to 2 decimal places. All capacitors were initially discharged. at t = 0, S1 is placed at position 1 and S2 is closed. At t = 15 ms, S1 is placed at position 2 and S2 is kept closed. At t = 25 ms, S1 is kept at position 2 and S2 is opened. Data: V1 = 19 V; R1 = 7.5 kΩ, R2 = 5 kΩ, R3 = 2.0 kΩ, R4 = 2 kΩ, R5 = 20 kΩ, R6 = 9.0 kΩ; C1 = 4.5 µF, C2 = 6.0 µF, C3 = 13 µF