The differential equation is: d²y k (y+s+l – h + mg dt2 m k The form of the solution that we consider now is: y(t) = yo + A cos(wt + 4) Solve for yo (in cm) with these parameters. If you need more information, enter -100000. • s = 9 cm • h = 167 cm •m = 500 grams • e = (relaxed length) = 7 cm k = (spring constant) = 0.05 N/cm If you are stumped, try this substitution: t = = (1/2 – 4)/w.

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter9: Relativity
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Problem 2CQ: Explain why, when defining the length of a rod, it is necessary to specify that the positions of the...
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The differential equation is:
d²y
k
(y+s+l – h +
mg
dt2
m
k
The form of the solution that we consider now is:
y(t) = yo + A cos(wt + 4)
Solve for yo (in cm) with these parameters. If you need more information, enter -100000.
• s = 9 cm
• h = 167 cm
•m = 500 grams
• e = (relaxed length) = 7 cm
k = (spring constant) = 0.05 N/cm
If you are stumped, try this substitution: t = (T/2 –e)/w.
Transcribed Image Text:The differential equation is: d²y k (y+s+l – h + mg dt2 m k The form of the solution that we consider now is: y(t) = yo + A cos(wt + 4) Solve for yo (in cm) with these parameters. If you need more information, enter -100000. • s = 9 cm • h = 167 cm •m = 500 grams • e = (relaxed length) = 7 cm k = (spring constant) = 0.05 N/cm If you are stumped, try this substitution: t = (T/2 –e)/w.
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