The dissociation of acetic acid, CH,COOH, has an equilibrium constant at 25°C of 1.8 x 10-5. CH,COOH(aq) =CH,COO-(aq) + H*(aq) If the equilibrium concentration of CH,COOH is 0.46 moles in 0.500 L of water and that of CH,COO is 8.1 x 10-3 moles in the same 0.500 L, calculate tl

Chemistry for Engineering Students
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Author:Lawrence S. Brown, Tom Holme
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.72PAE
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The dissociation of acetic acid, CH,COOH, has an
equilibrium constant at 25°C of 1.8 x 10-5.
CH,COOH(aq) = CH,COO-(aq) + H*(aq)
If the equilibrium concentration of CH,COOH is
0.46 moles in 0.500 L of water and that of CH,CO
is 8.1 x 10-3 moles in the same 0.500 L, calculate the
concentration of H+ for the reaction.
Transcribed Image Text:The dissociation of acetic acid, CH,COOH, has an equilibrium constant at 25°C of 1.8 x 10-5. CH,COOH(aq) = CH,COO-(aq) + H*(aq) If the equilibrium concentration of CH,COOH is 0.46 moles in 0.500 L of water and that of CH,CO is 8.1 x 10-3 moles in the same 0.500 L, calculate the concentration of H+ for the reaction.
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