The drawing shows two boxes resting on frictionless ramps. One box is relatively light and sits on a steep ramp. The other box is heavier and rests on a ramp that is less steep. The boxes are released from rest at A and allowed to slide down the ramps. The two boxes have masses of 14 and 33 kg. If A and B are 4.5 and 1.0 m, respectively, above the ground, determine the speed of (a) the lighter box and (b) the heavier box when each reaches B. (c) What is the ratio of the kinetic energy of the heavier box to that of the lighter box at B?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter5: Energy
Section: Chapter Questions
Problem 38P: Two blocks are connected by a light string that passes over a frictionless pulley as in Figure...
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The drawing shows two boxes resting on frictionless ramps. One box is relatively light and sits on a steep ramp. The other box is
heavier and rests on a ramp that is less steep. The boxes are released from rest at A and allowed to slide down the ramps. The two
boxes have masses of 14 and 33 kg. If A and B are 4.5 and 1.0 m, respectively, above the ground, determine the speed of (a) the lighter
box and (b) the heavier box when each reaches B. (c) What is the ratio of the kinetic energy of the heavier box to that of the lighter box
at B?
VA = 0 m/s
VA = 0 m/s
Ax
BA
B
B
Units
(a) VB=
Number i
(b) VB =
Number i
Units
KEheavier
Units
(c)
Number i
КЕ
Transcribed Image Text:The drawing shows two boxes resting on frictionless ramps. One box is relatively light and sits on a steep ramp. The other box is heavier and rests on a ramp that is less steep. The boxes are released from rest at A and allowed to slide down the ramps. The two boxes have masses of 14 and 33 kg. If A and B are 4.5 and 1.0 m, respectively, above the ground, determine the speed of (a) the lighter box and (b) the heavier box when each reaches B. (c) What is the ratio of the kinetic energy of the heavier box to that of the lighter box at B? VA = 0 m/s VA = 0 m/s Ax BA B B Units (a) VB= Number i (b) VB = Number i Units KEheavier Units (c) Number i КЕ
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